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Gennadij [26K]
3 years ago
10

What's the selling price if the markup is 45% and the cost to store 130

Mathematics
1 answer:
marta [7]3 years ago
4 0

Answer:

14.50

Step-by-step explanation:

I'd appreciate a like B)

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4(x+2)=4x+8 need help
alisha [4.7K]

Answer:

The answer is all real numbers

Step-by-step explanation:

4(x + 2) = 4x +8

Distribute the 4:

4x + 8 = 4x + 8

Then subtract 4x and 8 from both sides

0 = 0

This statement is true so its all real numbers

3 0
3 years ago
Read 2 more answers
Need help simplifying please.
qwelly [4]

Answer:

14x² + 7y - 22

Step-by-step explanation:

Combine like terms.

5x² - 6y - 22 + 13y + 9x²

5x² + 9x² = 14x²

-6y + 13y = 7y

Reorder the terms.

14x² + 7y - 22

Hope that helps.

7 0
3 years ago
1,535,744 what is the place of value of the number above?
hoa [83]

The place value is In the millions

8 0
3 years ago
I need to know the answer to question 10
motikmotik
The answer is actually e although it would have been a

6 0
3 years ago
A printer needs to make a poster that will have a total of 500 cm2 that will have 3 cm margins on the sides and 2 cm margins on
goblinko [34]

Answer:

The largest printed area is 381.43 cm^2 .

Step-by-step explanation:

The width of the full poster = 500/x

Length of the printed area = l =x - 4

Width of the printed area = w = (500/x) - 2

Area of the printed space = (x - 4) × ((500/x) - 2)

Now, take derivative of the area

A' = (x - 4)×(-500/x^2) + ((500/x) - 2)

A' = (2000/x^2) - 2

A' = (2000-2x^2) / x^2

put derivative equal to zero like A' = 0

(2000-2x^2) / x^2 = 0

2000 = 2x^2

x^2 = 1000

x = 31.62

So, the length of the original poster is = x = 31.62 cm

The width of the full poster = 500/x = 15.81 cm

l = x - 4 = 27.62

w = 500/x - 2 = 13.81

Therefore, The area of space available for printing is = l × w

= 27.62 × 13.81 = 381.43 cm^2 .

5 0
3 years ago
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