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devlian [24]
2 years ago
6

Help please! thank you

Mathematics
2 answers:
saveliy_v [14]2 years ago
7 0
The answer should be
a= 0.62
b= 7/9
c= 10/9
Lorico [155]2 years ago
3 0

Answer:

use a hint it usally helps me

Step-by-step explanation:

You might be interested in
A rectangular prism has a volume of 16cm^3 and a total surface area of 40cm^2. A similar prism has length 10 in., width 5 in. an
krok68 [10]
The volume is twice that of the cube of width, so the width of the original prism is
.. ∛(16 cm³/2) = 2 cm

Length = 4 cm
Width = 2 cm
Height = 2 cm
5 0
3 years ago
Help me please i jave 10 min left HELP​
yaroslaw [1]

Answer:

Option (A).

Step-by-step explanation:

8\frac{4}{5} is a mixed fraction and can be written as,

8\frac{4}{5}=8+\frac{4}{5} [Combination of a whole number and a fraction]

When we multiply this mixed fraction by 7,

7\times 8\frac{4}{5}=7\times (8+\frac{4}{5})

          =(7\times 8)+(7\times \frac{4}{5}) [Distributive property → a(b + c) = a×b + a×c]

          =56+\frac{28}{5}

          =56+5\frac{3}{5}

          =56+5+\frac{3}{5}

          =61+\frac{3}{5}

          =61\frac{3}{5}

Therefore, 7\times 8\frac{4}{5}=61\frac{3}{5} will be the answer.

Option (A) will be the correct option.

7 0
2 years ago
What is the relationship between Za and Zb?
Nesterboy [21]

Answer: B

Step-by-step explanation:

∠a and ∠b are complementary angles. Complementary angles are two angles adjacent to each other that add up to 90°. We know this is true because of the 90° angle that is labelled.

Vertical angles are not adjacent to each other. They are across from each other, connected by the angle. They are equal in angles. It is clear that ∠a and ∠b are not equal in angles. Therefore, they are complementary angles.

6 0
3 years ago
Prove the following statement using a proof by contraposition. Yr EQ,s ER, if s is irrational, then r + 1 is irrational.
sp2606 [1]

Answer:

I think that what you are trying to show is:  If s is irrational and r is rational, then r+s  is rational. If so, a proof can be as follows:

Step-by-step explanation:

Suppose that r+s is a rational number. Then r and r+s can be written as follows

r=\frac{p_{1}}{q_{1}}, \,p_{1}\in \mathbb{Z}, q_{1}\in \mathbb{Z}, q_{1}\neq 0

r+s=\frac{p_{2}}{q_{2}}, \,p_{2}\in \mathbb{Z}, q_{2}\in \mathbb{Z}, q_{2}\neq 0

Hence we have that

r+s=\frac{p_{1}}{q_{1}}+s=\frac{p_{2}}{q_{2}}

Then

s=\frac{p_{2}}{q_{2}}-\frac{p_{1}}{q_{1}}=\frac{p_{2}q_{1}-p_{1}q_{2}}{q_{1}q_{2}}\in \mathbb{Q}

This is a contradiction because we assumed that s is an irrational number.

Then r+s must be an irrational number.

3 0
2 years ago
PLEASE find the equation for this graph
Verdich [7]
I think it’s y=1/2x-10
6 0
1 year ago
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