Someone please help mad make sure it’s right please!!!!

What is the solution set for 5(3 – x) < – 2x +6 ?

maks197457 [2]

$5(3 - x) < - 2x + 6$

$15 - 5x < - 2x + 6$

$15 - 6 < - 2x + 5x$

$9 < 3x$

$\frac{9}{3} < x$

$3 < x$

All real numbers greater than 3

4 0

3 years ago

Express the following in the form p/q , where p and q are integers and q is not equal to 0<br> 0.47

Gennadij [26K]

Given,
0.47
X= 0.47
10x = 4.7

100x = 47.7

90X = 43

X = 43/90

p/q= 43/90

4 0

3 years ago

PLEASE HELP!

Oliga [24]

Answer:

C. 8/30 is your answer.

Step-by-step explanation:

What you do is you take each fraction and make it into a decimal.

6/24 = .25

We know that 1/4 is .25.

5/20 and 12/48 are also .25.

C. 8/30 is your answer.

3 0

4 years ago

Cesar has 32 boxes of pasta and 48 jars of sauce that he will be putting into bags for a food drive. He wants each bag to have t

zhannawk [14.2K]

Cesar has 32 boxes of pasta and 48 jars of sauce that he will be putting into bags for a food drive. He wants each bag to have the same amount of pasta and sauce and wants to use all of the items. Use the drop-down menus to complete the statements below about the number of bags Cesar can make.

What is the greatest number of bags Cesar can make and Each bag would have _____ pasta and _____ jars of sauce

Answer:

The greatest number of bags Cesar can make is 16 bags.

Each bag would have 2 pasta and 3 of jars of sauce

Step-by-step explanation:

We solve the above question using Greatest Common Factor method

The factors of 32 are: 1, 2, 4, 8, 16, 32

The factors of 48 are: 1, 2, 3, 4, 6, 8, 12, 16, 24, 48

Then the greatest common factor is 16.

Hence, the greatest number of bags Cesar can make is 16 bags.

For Pasta, We have 32 pasta

Each bag would have: 32/16

= 2 pasta

For Jars of sauce, we have 48 jars of sauce.= 48/16

= 3 jars of sauce

4 0

3 years ago

Assume that there are an equal number of births in each month so that the probability is that a person chosen at random was born

NikAS [45]

Answer:

0.2773 = 27.73% probability that at the May celebration, exactly two members of the group have May birthdays

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they have a birthday in May, or they do not. The probability of a person having a birthday in May is independent of any other person. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$