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3 years ago

Write two forms for 40,023,032

Mathematics

1 answer:

Tema [17]3 years ago

3 0

Fourty million, twenty-three thousand, thirty-two.

40,000,000 + 20,000 + 3,000 + 30 + 2

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(50 points)<br><br><br><br> NEED ANSWER ASAPPPP:)

lbvjy [14]

5-10(|0.8-3/6|)

5-10(|1/5|)

5-(10)(0.2)

5-2

=3, so C would be your best answer.

5 0

3 years ago

Read 2 more answers

Math help :) Thank you!

Maru [420]

Answer:

1/2

Step-by-step explanation:

Total number of cards in a deck = 52

Total umber of red cards = 13 + 13 = 26

P(red card)

= 26/52

= 1/2

6 0

3 years ago

PLS HELP ME GRADES ARE DUE TODAY! Fill in the chart below based on the graphs. Remember: Slope is vertical change divided by hor

blagie [28]

Answer:

VC , HC , S

A) 6 , 3 , 2

b) 8 , 2 , 4

c) 40 , 20 , 2

4 0

3 years ago

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An old bone contains 80% of its original carbon-14. Use the half-life model to find the age of the bone. Find an equation equiva

Ira Lisetskai [31]

Answer:

An old bone contains 80% of its original carbon-14 in 1844.6479 years

Step-by-step explanation:

We know that

half life time of C-14 is 5730 years

so, h=5730

now, we can use formula

$P(t)=P_0(\frac{1}{2})^{\frac{t}{h} }$

we can plug back h

and we get

$P(t)=P_0(\frac{1}{2})^{\frac{t}{5730} }$

An old bone contains 80% of its original carbon-14

so,

P(t)=0.80Po

we can plug it and then we solve for t

$0.80P_0=P_0(\frac{1}{2})^{\frac{t}{5730} }$

$0.80=(\frac{1}{2})^{\frac{t}{5730} }$

$\ln \left(0.8\right)=\ln \left(\left(\frac{1}{2}\right)^{\frac{t}{5730}}\right)$

$t=-\frac{5730\ln \left(0.8\right)}{\ln \left(2\right)}$

$t=1844.6479$

So,

An old bone contains 80% of its original carbon-14 in 1844.6479 years

4 0

3 years ago

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What two numbers that you multiply to equal 96?

Lady_Fox [76]

3 and 32

Step-by-step explanation: 32 *3 equals 96

3 0

4 years ago

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