Answer:
x = -2
Step-by-step explanation:
The given equation is a multi-step equation since it has the variable on both sides of the equal sign. However, the goal of any equation is to isolate the variable (get it by itself) by using inverse (opposite) operations to get the variable on one side of the equal sign and the numbers on the other.
5x - 5 = 3x - 9
1. Subtract '3x' from both sides:
5x - 3x - 5 = 3x - 3x - 9
2x - 5 = -9
2. Add '5' to both sides:
2x - 5 + 5 = -9 + 5
2x = -4
3. Divide '2' from both sides:
2x/2 = -4/2
x = -2
Circumference is Diameter * 3.14
so D * 3.14 = 31.4
31.4 / 3.14 = 10 so the diameter is 10.
the radius is half of the diameter so radius = 5 centimeters.
125
2^3 = 8
8 = 1/2 of 16
1/2 of 250 = 125
Answer:
![\large\boxed{x=1,\ y=6\to(1,\ 6)}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7Bx%3D1%2C%5C%20y%3D6%5Cto%281%2C%5C%206%29%7D)
Step-by-step explanation:
![\left\{\begin{array}{ccc}-6x=48-6y&\text{change the signs}\\-4x=50-6y\end{array}\right\\\underline{+\left\{\begin{array}{ccc}6x=-48+6y\\-4x=50-6y\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad2x=2\qquad\text{divide both sides by 2}\\.\qquad x=1\\\\\text{Put it ot the first equation:}\\-6(1)=48-6y\\-6=48-6y\qquad\text{subtract 48 from both sides}\\-54=-6y\qquad\text{divide both sides by (-6)}\\9=y\to y=6](https://tex.z-dn.net/?f=%5Cleft%5C%7B%5Cbegin%7Barray%7D%7Bccc%7D-6x%3D48-6y%26%5Ctext%7Bchange%20the%20signs%7D%5C%5C-4x%3D50-6y%5Cend%7Barray%7D%5Cright%5C%5C%5Cunderline%7B%2B%5Cleft%5C%7B%5Cbegin%7Barray%7D%7Bccc%7D6x%3D-48%2B6y%5C%5C-4x%3D50-6y%5Cend%7Barray%7D%5Cright%7D%5Cqquad%5Ctext%7Badd%20both%20sides%20of%20the%20equations%7D%5C%5C.%5Cqquad2x%3D2%5Cqquad%5Ctext%7Bdivide%20both%20sides%20by%202%7D%5C%5C.%5Cqquad%20x%3D1%5C%5C%5C%5C%5Ctext%7BPut%20it%20ot%20the%20first%20equation%3A%7D%5C%5C-6%281%29%3D48-6y%5C%5C-6%3D48-6y%5Cqquad%5Ctext%7Bsubtract%2048%20from%20both%20sides%7D%5C%5C-54%3D-6y%5Cqquad%5Ctext%7Bdivide%20both%20sides%20by%20%28-6%29%7D%5C%5C9%3Dy%5Cto%20y%3D6)
Any examples?
Or what do you mean?