Answer:
![JK = 2](https://tex.z-dn.net/?f=JK%20%3D%202)
Step-by-step explanation:
Given:
![JK = 2x](https://tex.z-dn.net/?f=JK%20%3D%202x)
![IJ = 5x](https://tex.z-dn.net/?f=IJ%20%3D%205x)
![IK = x + 6](https://tex.z-dn.net/?f=IK%20%3D%20x%20%2B%206)
Required
Solve for JK.
Since J is on IK, we have:
![IK = IJ + JK](https://tex.z-dn.net/?f=IK%20%3D%20IJ%20%2B%20JK)
![x + 6 = 5x + 2x](https://tex.z-dn.net/?f=x%20%2B%206%20%3D%205x%20%2B%202x)
![x + 6 = 7x](https://tex.z-dn.net/?f=x%20%2B%206%20%3D%207x)
Collect Like Terms
![7x - x = 6](https://tex.z-dn.net/?f=7x%20-%20x%20%3D%206)
![6x = 6](https://tex.z-dn.net/?f=6x%20%3D%206)
Solve for x
![x = 6/6](https://tex.z-dn.net/?f=x%20%3D%206%2F6)
![x = 1](https://tex.z-dn.net/?f=x%20%3D%201)
Substitute 1 for x in ![JK = 2x](https://tex.z-dn.net/?f=JK%20%3D%202x)
![JK = 2 * 1](https://tex.z-dn.net/?f=JK%20%3D%202%20%2A%201)
![JK = 2](https://tex.z-dn.net/?f=JK%20%3D%202)
Yes, It would be reasonable since thats about the weight of a skateboard.
However, the average skateboard is closer to 6 pounds. So, the skateboard in the question is very possible- but it would be really low quality.
However- given that you are in middle school- I would say yes, it is reasonable.
Trying to factor by splitting the middle term
Factoring <span> b2-4b+4</span>
The first term is, <span> <span>b2</span> </span> its coefficient is <span> 1 </span>.
The middle term is, <span> -4b </span> its coefficient is <span> -4 </span>.
The last term, "the constant", is <span> +4 </span>
Step-1 : Multiply the coefficient of the first term by the constant <span> 1 • 4 = 4</span>
Step-2 : Find two factors of 4 whose sum equals the coefficient of the middle term, which is <span> -4 </span>.
<span><span> </span></span>
<span><span>-4 + -1 = -5</span><span> -2 + -2 = -4 That's it</span></span>
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -2 and -2
<span>b2 - 2b</span> - 2b - 4
Step-4 : Add up the first 2 terms, pulling out like factors :
b • (b-2)
Add up the last 2 terms, pulling out common factors :
2 • (b-2)
Step-5 : Add up the four terms of step 4 :
(b-2) • (b-2)
Which is the desired factorization