Check the picture below.
so let's use the law of sines then
![\textit{Law of sines} \\\\ \cfrac{sin(\measuredangle A)}{a}=\cfrac{sin(\measuredangle B)}{b}=\cfrac{sin(\measuredangle C)}{c} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{1.9}{sin(Z)}~~ = ~~\cfrac{XZ}{sin(Y)}\implies \cfrac{1.9}{sin(89^o)}~~ = ~~\cfrac{XZ}{sin(70^o)}\implies \cfrac{1.9\cdot sin(70^o)}{sin(89^o)}=XZ \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Ctextit%7BLaw%20of%20sines%7D%20%5C%5C%5C%5C%20%5Ccfrac%7Bsin%28%5Cmeasuredangle%20A%29%7D%7Ba%7D%3D%5Ccfrac%7Bsin%28%5Cmeasuredangle%20B%29%7D%7Bb%7D%3D%5Ccfrac%7Bsin%28%5Cmeasuredangle%20C%29%7D%7Bc%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Ccfrac%7B1.9%7D%7Bsin%28Z%29%7D~~%20%3D%20~~%5Ccfrac%7BXZ%7D%7Bsin%28Y%29%7D%5Cimplies%20%5Ccfrac%7B1.9%7D%7Bsin%2889%5Eo%29%7D~~%20%3D%20~~%5Ccfrac%7BXZ%7D%7Bsin%2870%5Eo%29%7D%5Cimplies%20%5Ccfrac%7B1.9%5Ccdot%20sin%2870%5Eo%29%7D%7Bsin%2889%5Eo%29%7D%3DXZ%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)

quick observation, the picture of the triangle is very misleading, since those angles as drawn are not good representers of the angles values.
Answer:
10
Step-by-step explanation:
P = 2h - 250......ur equation
A. Is your answer because it’s doesn’t go that in-depth in the answer.
Hope I helped
Answer:
y=1/3
Step-by-step explanation:
3y+1=0
3y=-1
3y/3=-1/3
y=-1/3