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defon
3 years ago
6

Find the value of x.

Mathematics
1 answer:
3241004551 [841]3 years ago
8 0

Answer:

x= 48

exterior angle theorem

-12+48 = 36

48x3= 144

36+134= 180

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Find an expression for a cubic function f if f(4) = 96 and f(-4) = f(0) = f(5) = 0. Part 1 of 4 A cubic function generally has t
Bezzdna [24]

Given a polynomial p(x) and a point x_0, we have that

p(x_0) = 0 \iff (x-x_0) \text{\ divides\ } p(x)

We know that our cubic function is zero at -4, 0 and 5, which means that our polynomial is a multiple of

(x+4)(x)(x-5) = x(x+4)(x-5)

Since this is already a cubic polynomial (it's the product of 3 polynomials with degree one), we can only adjust a multiplicative factor: our function must be

f(x) = ax(x+4)(x-5),\quad a \in \mathbb{R}

To fix the correct value for a, we impose f(4)=96:

f(4) = 4a(4+4)(4-5) = -32a = 96

And so we must impose

-32a=96 \iff a = -\dfrac{96}{32} = -3

So, the function we're looking for is

f(x) = -3x(x+4)(x-5)=-3x^3+3x^2+60x

4 0
3 years ago
A nursery has 10 tree seedlings to give out at 2 workshops. It wants to give out a minimum of 2 seedlings at each workshop. How
11111nata11111 [884]

We are given total 10 tree seedlings.

Number of workshops = 2.

Here order doesn't matters.

<em>When order doesn't matters we apply combination.</em>

We know formula of combination:

C(n,r) = \frac{n!}{r!(n-r)!}

For the given situation, we have

n=10 and r=2.

Plugging values in formula, we get

\frac{10!}{2!(10-8)!}  = \frac{10\times 9\times8!}{2!8!}

\frac{10 \times 9}{2} = \frac{90}{2} =45

<h3>Therefore, 45 different ways can the nursery give out seedlings.</h3>
5 0
3 years ago
Write two different rational functions whose graphs have the same end behaviour as the graph of y=3x^2
baherus [9]

Answer:

               y=x^2+5x+20\\ \\ y=8x^2+35

Explanation:

The <em>end behavior</em> of a <em>rational function</em> is the limit of the function as x approaches negative infinity and infinity.

Note that the the values of even functions are the same for ± x. That implies that their limits for ± ∞ are equal.

The limits of the quadratic function of general form y=ax^2+bx+c as x approaches negative infinity or infinity, when a  is positive, are infinity.

That is because as the absolute value of x gets bigger y becomes bigger too.

In mathematical symbols, that is:

\lim_{x \to -\infty}3x^2=\infty\\ \\ \lim_{x \to \infty}3x^2=\infty

Hence, the graphs of any quadratic function with positive coefficient of the quadratic term will have the same end behavior as the graph of y = 3x².

Two examples are:

         y=x^2+5x+20\\ \\ y=8x^2+35

5 0
3 years ago
2.2 Your friend Sam, mistakenly wrote down the multiples of 10 as: 1; 2; 5; and 10.
kkurt [141]
Do you know the multiples of 10
6 0
2 years ago
How far apart in feet are Marcus and Joel. Please round your answer to the nearest tenth of a foot
Pavel [41]

Answer:

The distance between Marcus and Joel is approximately 127.3 feet.

Step-by-step explanation:

The distances between Jean to Joel, Jean to Marcus and Marcus to Joel form a right triangle where the distance from Marcus to Joel is the hypothenuse. We can measure the distance from Jean to Marcus and Jean to Joel by using the grid provided, since they're along the same axis. This is shown below:

d(Jean, Marcus) = Jean(x) - Marcus(x) = 100 - 10 = 90 feet

d(Jean, Joel) = Jean(y) - Joel(y) = 90 - 0 = 90 feet

We can apply the pythagora's theorem to find the distance between Marcus and Joel.

d(Marcus,Joel)² = d(Jean,Marcus)² + d(Jean,Joel)²

d(Marcus,Joel)² = (90)² + (90)²

d(Marcus,Joel)² = 2*(90)²

d(Marcus, Joel) = sqrt(2*(90)²) = 90*sqrt(2) = 127.279 feet

The distance between Marcus and Joel is approximately 127.3 feet.

8 0
4 years ago
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