Please help me so confused Solve. x^2 + 3x − 7 = 0 Enter your answers, as exact values, in the boxes. x = or x =
2 answers:
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Answer:
There are an absolute minimum (x = 6) and an absolute maximum (x = 12).
Step-by-step explanation:
The correct statement is described below:
Find the absolute maximum and minimum values of the function below:
,
Given that function is a polynomial, then we have the guarantee that function is continuous and differentiable and we can use First and Second Derivative Tests.
First, we obtain the first derivative of the function and equalize it to zero:
(Eq. 1)
As we can see, only a solution is a valid critical value. That is:
Second, we determine the second derivative formula and evaluate it at the only critical point:
(Eq. 2)
x = 6
(Absolute minimum)
Third, we evaluate the function at each extreme of the given interval and the critical point as well:
x = 2
x = 6
x = 12
There are an absolute minimum (x = 6) and an absolute maximum (x = 12).
Answer:
The width of the box is 6.7 cm
The maximum volume is 148.1 cm³
Step-by-step explanation:
The given parameters of the box Jorge is asked to build are;
The maximum girth of the box = 20 cm
The nature of the sides of the box = 2 square sides and 4 rectangular sides
The side length of square side of the box = w
The length of the rectangular side of the box = l
Therefore, we have;
The girth = 2·w + 2·l = 20 cm
∴ w + l = 20/2 = 10
w + l = 10
l = 10 - w
The volume of the box, V = Area of square side × Length of rectangular side
∴ V = w × w × l = w × w × (10 - w)
V = 10·w² - w³
At the maximum volume, we have;
dV/dw = d(10·w² - w³)/dw = 0
∴ d(10·w² - w³)/dw = 2×10·w - 3·w² = 0
2×10·w - 3·w² = 20·w - 3·w² = 0
20·w - 3·w² = 0 at the maximum volume
w·(20 - 3·w) = 0
∴ w = 0 or w = 20/3 = 6.
Given that 6. > 0, we have;
At the maximum volume, the width of the block, w = 6. cm ≈ 6.7 cm
The maximum volume, , is therefore given when w = 6.
cm = 20/3 cm as follows;
V = 10·w² - w³
= 10·(20/3)² - (20/3)³ = 4000/27 = 148.
The maximum volume, = 148.
cm³ ≈ 148.1 cm³
Using a graphing calculator, also, we have by finding the extremum of the function V = 10·w² - w³, the coordinate of the maximum point is (20/3, 4000/27)
The width of the box is;
6.7 cm
The maximum volume is;
148.1 cm³
