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3 years ago

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Help please!!!!!!!!!!!!!!!

1 answer:

anygoal [31]3 years ago

3 0

-1. hope that helps!

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Hello There!!~ (^人^) I need help please... Sasha noticed that the graph of the sales of yearbooks represented a proportional rel

zzz [600]

Answer:

Sasha can look at the graph and check to see that when she plots the points on the graph, they end up as a straight line. She can also draw a table to test the values and see if when you divide y/x you get the same answer for all of them.

Step-by-step explanation:

5 0

3 years ago

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Monica has walked 3/2 miles in 2/3 of an hour. How many miles can Monica walk in one hour?

defon

Answer:

<u>2.25 Miles</u> is how many miles Monica can walk <u>in one hour</u>.

Step-by-step explanation:

You take 3/2 which is 1.5 in decimal form then take the 2 out of 2/3 divide 1.5 by 2, you get 0.75 then you add 0.75 to 1.5 and <u>you get 2.25 which is how many miles she walks in one hour.</u>

3 0

2 years ago

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(3.8 x 10 ^ -6) x (2.37 x 10 ^ -3)<br><br> Enter the answer in science notification

Black_prince [1.1K]

Multiply the coefficients and the powers of 10 with each other:

$(3.8 \times 10^{-6}) \times (2.37 \times 10^{-3}) = (3.8\times2.37) \times (10^{-6} \times10^{-3})$

The numeric part simply yields

$3.8\times2.37 = 9.006$

As for the powers of 10, you have to add the exponents, using the rule

$a^b \times a^c = a^{b+c}$

So, we have

$10^{-6} \times10^{-3} = 10^{-6-3} = 10^{-9}$

So, the final answer is

$9.006\times 10^{-9}$

7 0

2 years ago

Use the equation and type the ordered-pairs. y = log 3 x {(1/3, a0), (1, a1), (3, a2), (9, a3), (27, a4), (81, a5)

vagabundo [1.1K]

Answer:

Considering the given equation $y = log_{3}x\\$

And the ordered pairs in the format $(x, y)$

I don't know if it is log of base 3 or 10, but I will assume it is 3.

For $(\frac{1}{3}, a_{0} )$

$x=\frac{1}{3}$

$y=a_{0}$

$y = log_{3}x\\y = log_{3}(\frac{1}{3} )\\y=-\log _3\left(3\right)\\y=-1$

So the ordered pair will be $(\frac{1}{3}, -1 )$

For $(1, a_{1} )$

$x=1$

$y=a_{1}$

$y = log_{3}x\\y = log_{3}1\\y = log_{3}(1)\\Note: \log _a(1)=0\\y = 0$

So the ordered pair will be $(1, 0 )$

For $(3, a_{2} )$

$x=3$

$y=a_{2}$

$y = log_{3}x\\y = log_{3}3\\y = 1$

So the ordered pair will be $(3, 1 )$

For $(9, a_{3} )$

$x=9$

$y=a_{3}$

$y = log_{3}x\\y = log_{3}9\\y=2\log _3\left(3\right)\\y=2$

So the ordered pair will be $(9, 2 )$

For $(27, a_{4} )$

$x=27$

$y=a_{4}$

$y = log_{3}x\\y = log_{3}27\\y=3\log _3\left(3\right)\\y=3$

So the ordered pair will be $(27, 3 )$

For $(81, a_{5} )$

$x=81$

$y=a_{5}$

$y = log_{3}x\\y = log_{3}81\\y=4\log _3\left(3\right)\\y=4$

So the ordered pair will be $(81, 4 )$

4 0

3 years ago

What is the first quartile of the box-and-whisker plot?

iogann1982 [59]

B) 48 is your answer

Hope this helps!!

6 0

3 years ago

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