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marysya [2.9K]
2 years ago
13

Find the equation of the line that passes through the points (3,4) and (6,2)

Mathematics
1 answer:
umka2103 [35]2 years ago
4 0
<h3>Answer</h3><h2>{EQUATION}</h2>

<h3>*Twice a number increased by four is ten.</h3><h3>*The difference of a number and 2 is 5. </h3>

<h2>{EXPRESSION}</h2>

<h3>*Seven less than half a number squared.</h3><h3>*The difference of a number and two is five. </h3>
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The inventor of a new game believes that the variable cost for producing the game is $0.90 per unit and the fixed costs are $620
nikdorinn [45]

Answer:

Step-by-step explanation:

Let x represent the number of units of games sold.

The inventor of a new game believes that the variable cost for producing the game is $0.90 per unit and the fixed costs are $6200. It means that the total variable cost for x units would be

0.9 × x = 0.9x

The inventor sells each game for $1.69. This means that the total revenue from x units of games sold would be

1.69 × x = 1.69x

The total cost for a business is the sum of the variable cost and the fixed costs. Therefore, the total cost for the number of games sold would be

C = 6200 + 0.9x

Profit = Revenue - total cost

Therefore,

Profit = 1.69x - (6200 + 0.9x)

= 1.69x - 0.9x - 6200

= 0.79x - 6200

8 0
3 years ago
Please answer the following questions​
laila [671]

Answer:

4a) 110 square centimetres

4b) 127 square centimetres

6) 292 square centimetres

8) 800 tiles

Step-by-step explanation:

4. We need to find the area of the large rectangle and then deduct the area of the unshaded part:

a) The large rectangle has dimensions 12 cm by 15 cm. Its area is:

A = 12 * 15 = 180 square centimetres

The unshaded part has a length of 15 - (3 + 2) cm i.e. 10 cm and a width of 7 cm. Its area is:

a = 10 * 7 = 70 square centimetres

Therefore, the area of the shaded part is:

A - a = 180  - 70 = 110 square centimetres

b) The large rectangle has dimensions 13 cm by 11 cm. Its area is:

A = 13 * 11 = 143 square centimetres

The unshaded part has dimensions 8 cm by 2 cm. Its area is:

a = 8 * 2 = 16 square centimetres

Therefore, the area of the shaded part is:

A - a = 143 - 16 = 127 square centimetres

6. The background area of the space not covered by the photograph is the area of the frame minus the area of the photograph.

The frame has dimensions 24 cm by 18 cm. Therefore, its area is:

A = 24 * 18 = 432 square centimetres

The photograph has dimensions 14 cm by 10 cm. Therefore, its area is:

a = 14 * 10 = 140 square centimetres

Therefore, the background area of the space not covered by the photograph is:

A - a = 432 - 140 = 292 square centimetres

8) The floor has dimensions 8 m by 4 m. The area of the floor is:

A = 8 * 4 = 32 square centimetres

Each square tile has dimensions 20 cm by 20 cm. In metres, that is 0.2 m by 0.2 m. The area of each tile is:

a = 0.2 * 0.2 = 0.04 square metres

The number of tiles that are needed is the area of the floor divided by the area of each tile:

A / a = 32 / 0.04 = 800 tiles

4 0
4 years ago
Alexis is knitting a blanket 2 meters long. Every 2 decimeters, she changes the color of the yarn to make stripes. How many stri
IgorC [24]

Answer:

There are 10 stripes in the blanket.

Step-by-step explanation:

We are given the following in the question:

Length of blanket = 2 meters

1 meter = 10 decimeter

Length of blanket in decimeter =

2\times 10 = 20\text{ decimeters}

Change of color = Every 2 decimeters.

Number of stripe =

=\dfrac{\text{Length of blanket}}{\text{Length of change of color of stripe}}\\\\=\dfrac{20}{2} = 10

Thus, there are 10 stripes in the blanket.

3 0
4 years ago
While mining, Nancy found a large metal bar that weighed 24 ounces, Nancy was also able to determine that the bar had 18 ounces
lord [1]

Answer:

%75

Step-by-step explanation:

4 0
3 years ago
Find the greatest common factor of 63 and 42
Andru [333]
Greatest common factor (GCF) of 42 and 63 is 21. We will now calculate the prime factors of 42 and 63, than find the greatest common factor (greatest common divisor (gcd)) of the numbers by matching the biggest common factor of 42 and 63.
4 0
4 years ago
Read 2 more answers
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