What value of n makes the equation true 1 2 10 30

puteri [66]

let's recall the vertical line test, if a vertical line hits the graph or points twice, then is NOT a function. Check the picture below.

6 0

1 year ago

Read 2 more answers

The height of a toy rocket that is shot in the air with an upward velocity of 48 feet per second can be modeled by the function

Irina18 [472]

Answer:

B) 36 ft

Step-by-step explanation:

Given:

The height as a function of time is given as:

$f(t)=-16t^2+48t$

At maximum height, the instantaneous velocity becomes 0. The instantaneous velocity is the first derivative of the height function.

So, the derivative of the the given function is 0 at the maximum height.

Differentiating the above function with time, we get

$f'(t)=\frac{d}{dt}(-16t^2)+\frac{d}{dt}(48t)\\f'(t)=-32t+48$

Now, equating the derivative to 0 and finding time.

$f'(t)=0\\-32t+48=0\\32t=48\\t=\frac{48}{32}=1.5\ s$

Therefore, time taken to reach maximum height is 1.5 s.

Now, maximum height is obtained by plugging in $t=1.5$ in the height equation.

Maximum height is given as:

$h_{max}=-16(1.5)^2+48(1.5)\\h_{max}=-16\times 2.25+72\\h_{max}=-36+72\\h_{max}=36\ ft$

4 0

3 years ago

Read 2 more answers

The difference between ten times a number and eight times the number is negative ten

IRINA_888 [86]

10n - 8n = -10

Hope this helps!

6 0

3 years ago

Read 2 more answers

Use the distributive property to remove the parentheses.

velikii [3]

Answer:

well the correct answer is 12×75.0=140

75

well 215 -2w

4 0

3 years ago

A passcode can have 5 or 6 digits. Digits can be repeated and leading 0s are allowed. So, 1234 would be a 4 digit code that is d

sergiy2304 [10]

Answer:

The number of passcodes possible is 1,100,000

Step-by-step explanation:

Here , we want to calculate the number of different possible passcodes.

For the five digit code,

each number in the code has a possibility of choosing from the digits 0 to 9, so this means that each of the numbers in the code has 10 options.

So for a five digit code, the number of possible choices would be 10 * 10 * 10 * 10 * 10 = 10^5

For a six digit code, the number of possible choice would be 10 * 10 * 10 * 10 * 10 * 10 * 10 = 10^6

So for 5 or 6 digits code, the number of possible choices would be;

10^5 + 10^6 = 10^5(1 + 10)

= 11(10^5) = 1,100,000

5 0

3 years ago