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2 years ago

5

Who can help me with this question problem

1 answer:

german2 years ago

8 0

Answer:

use the formula and evaluate the givens

Step-by-step explanation:

336=(14/11)^2 * 22/7*h

336=196/121 * 22/7h

336= 4312/847h

336= 5.09h

h=66

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PLZZZ HELP 30 POINTS!!!!!!!

djverab [1.8K]

Answer:

150

Step-by-step explanation:

150

6 0

2 years ago

In a sample of 700 gas stations, the mean price for regular gasoline at the pump was $2.894 per gallon and the standard deviati

frez [133]

Answer:

$P(x < 2.892) = 4.36\%$

Step-by-step explanation:

Given

$N = 700$ --- Population

$\mu = 2.894$ -- Mean

$\sigma = 0.009$ --- Standard deviation

$n = 55$ -- Sample

Required: $P(x < 2.892)$

This question will be solved using the finite correction factor

First, calculated the z score

$z = \frac{x - \mu}{\sqrt{\frac{N -n}{N -1}} * \frac{\sigma}{\sqrt n}}$

$z = \frac{2.892 - 2.894}{\sqrt{\frac{700 -55}{700 -1}} * \frac{0.009}{\sqrt {55}}}$

$z = \frac{-0.002}{\sqrt{\frac{645}{699}} * \frac{0.009}{7.42}}$

$z = \frac{-0.002}{\sqrt{0.92} * \frac{0.009}{7.42}}$

$z = \frac{-0.002}{0.95917 * 0.0012129}$

$z = -1.71$

So:

$P(x < 2.892) = P(z < -1.71)$

Using z table

$P(x < 2.892) = 0.043633$

$P(x < 2.892) = 4.36\%$

3 0

3 years ago

Use induction to prove: For every integer n > 1, the number n5 - n is a multiple of 5.

nignag [31]

Answer:

we need to prove : for every integer n>1, the number $n^{5}-n$ is a multiple of 5.

1) check divisibility for n=1, $f(1)=(1)^{5}-1=0$ (divisible)

2) Assume that $f(k)$ is divisible by 5, $f(k)=(k)^{5}-k$

3) Induction,

$f(k+1)=(k+1)^{5}-(k+1)$

$=(k^{5}+5k^{4}+10k^{3}+10k^{2}+5k+1)-k-1$

$=k^{5}+5k^{4}+10k^{3}+10k^{2}+4k$

Now, $f(k+1)-f(k)$

$f(k+1)-f(k)=k^{5}+5k^{4}+10k^{3}+10k^{2}+4k-(k^{5}-k)$

$f(k+1)-f(k)=k^{5}+5k^{4}+10k^{3}+10k^{2}+4k-k^{5}+k$

$f(k+1)-f(k)=5k^{4}+10k^{3}+10k^{2}+5k$

Take out the common factor,

$f(k+1)-f(k)=5(k^{4}+2k^{3}+2k^{2}+k)$ (divisible by 5)

add both the sides by f(k)

$f(k+1)=f(k)+5(k^{4}+2k^{3}+2k^{2}+k)$

We have proved that difference between $f(k+1)$ and $f(k)$ is divisible by 5.

so, our assumption in step 2 is correct.

Since $f(k)$ is divisible by 5, then $f(k+1)$ must be divisible by 5 since we are taking the sum of 2 terms that are divisible by 5.

Therefore, for every integer n>1, the number $n^{5}-n$ is a multiple of 5.

3 0

2 years ago

Identify the variable and the constant in the expression below. n + 3 variable: ___________________________ constant: __________

Ilya [14]

N is the variable and 3 is the constant.

8 0

2 years ago

Write 96% as a fraction.

RoseWind [281]

Answer:

Directly, it would be 96/100. However, we can reduce it to become 48/50 = <u>24/25.</u>

(underlined is simplest answer)

6 0

3 years ago

Read 2 more answers