Question

The sum of the angles of a triangle is 180. Find the three angles if one angle is twice the smallest angle and the third angle is 36 degrees greater than the smallest angle. Place them in order from least to greatest.

Answer 1

Now we have to,

find the three angles if one angle is twice smallest angle and third angle is 36° greater than smallest angle.

Then take the values as,

→ smallest angle = x

→ y = 2x

→ z = x + 36°

Let we find the angles,

→ x + y + z = 180°

→ x + 2x + x + 36° = 180°

→ 4x = 180 - 36

→ 4x = 144

→ x = 144/4

→ [x = 36°]

Now the value of y is,

→ y = 2x

→ y = 2 × 36°

→ [y = 72°]

Then the value of z is,

→ z = x + 36°

→ z = 36° + 36°

→ [z = 72°]

Placing values from least to greatest,

→ 36°, 72°, 72°

Hence, the order is 36°, 72°, 72°.

Answer 2

Answer:

• 36°, 72°, 72°

Step-by-step explanation:

The angles are x, y and z:

• x = 2y, z = y + 36

Their sum is:

• x + y + z = 180
• 2y + y + y + 36 = 180
• 4y = 144
• y = 36

Then find the other angles:

• x = 2*36 = 72
• z = 36 + 36 = 72