To find the product of (4x-5y)^2,
we can rewrite the problem as:
(4x-5y)(4x-5y) (two times because it is squared)
Now, time to use that old method we learned in middle school:
FOIL. (Firsts, Outers, Inners, and Lasts)
FOIL can help us greatly in this scenario.
Let's start by multiplying the 'Firsts' together:
4x * 4x = <em>16x^2</em>
Now, lets to the 'Outers':
4x * -5y = <em>-20xy</em>
Next, we can multiply the 'Inners':
-5y * 4x = <em>-20xy</em>
Finally, let's do the 'Lasts':
-5y * -5y = <em>25y</em>^2
Now, we can take the products of these equations from FOIL and combine like terms. We have: 16x^2, -20xy, -20xy, and 25y^2.
-20xy and -20xy make -40xy.
The final equation (product of (4x-5y)^2) is:
16x^2 - 40xy + 25y^2
Hope I helped! If any of my math is wrong, please report and let me know!
Have a good one.
Answer:
k≥-1.5
Step-by-step explanation:
-(5k-3) ≤ 15 + 3k
-5k+3 ≤15 +3k
+5k +5k
3≤15+8k
-15 -15
-12 ≤ 8k
divide both sides by 8
-1.5 ≤ k
or k≥-1.5
Hope this Helps!!!
I think the answer is the second on b
Answer:4=log(x)
For logarithmic equations, logᵇ(x)=y is equivalent to b∧y=x such that x>0,b>0, and b≠1.
In this case, b=10, x=x, and y=4.
