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dem82 [27]
3 years ago
15

Write a system of equations to describe the situation below, solve using substitution, and fill in the blanks.

Mathematics
1 answer:
Tems11 [23]3 years ago
3 0
The answer is =20 you can thank me later
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Select the correct answer.<br> Which graph shows a function and its inverse?
labwork [276]

Answer:

See below

Step-by-step explanation:

If a function is bijective and 1-to-1, then it will have an inverse function. Consequentially, they will be symmetrical about the line y=x, which is a diagonal line passing through the origin at a 45 degree angle.

None of the graphs look correct though, but it also seems that some options are cut out, so make sure to choose the correct graph given the characteristics I've previously described.

6 0
2 years ago
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Walking 10 blocks can cosume 75 calories. how many calories can you consume walking 25 blocks
Dominik [7]
Walking 10 blocks consumes 75 calories so... You add another 75 wich is calories and then divide 75/2. 75+75+37.5=187.5 calories!
6 0
3 years ago
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If Abby rolls two number cubes a hundred times, about how many times would she expect a product greater than 10.
alexandr1967 [171]

Answer:

20 times ??

Step-by-step explanation:

6 0
2 years ago
3. What is the solution set of the equation 3x + 5) = x + 2?
Simora [160]
The solution set of 3x+5=x+2 is x=-1. This is because you want to get the variables on one side and the numbers on the other. you subtract x on both sides and subtract 5 on both sides. your equation then becomes 3x=-3. you then divide 3 on both sides and you get your answer of x=-1.
3 0
3 years ago
Make B the subject of the relation : 1/a is equal to 1/b + c​
stealth61 [152]

Answer:

By making ‘a’ the subject, I believe you mean isolate the variable ‘a’.

1/a - 1/b = 1/c : add 1/b to both sides

1/a = 1/b + 1/c : combine the unlike fractions by finding a common denominator, bc is the common denominator

1/a = (1/b)(c/c) + (1/c)(b/b) : simplify

1/a = (c/bc) + (b/bc) : add numerators only, because the denominators match

1/a = (c + b)/bc : multiply both sides by a

1 = (a)[(c + b)/bc] : multiply both sides by the reciprocal of [(c + b)/bc] which is [bc/(b + c)]

1[bc/(b + c)] = a

a = bc/(b + c)

This will not work if c = -b, because then you would be dividing by zero.

Example: 1/2 - 1/3 = 1/6 a = 2, b = 3 c= 6

a = bc/(b + c) => 2 = (3 x 6)/(3 + 6) => 2 = 18/9 => 2 = 2.

Step-by-step explanation:

4 0
3 years ago
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