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4 years ago

Make B the subject of the relation : 1/a is equal to 1/b + c

Mathematics

1 answer:

stealth61 [152]4 years ago

4 0

Answer:

By making ‘a’ the subject, I believe you mean isolate the variable ‘a’.

1/a - 1/b = 1/c : add 1/b to both sides

1/a = 1/b + 1/c : combine the unlike fractions by finding a common denominator, bc is the common denominator

1/a = (1/b)(c/c) + (1/c)(b/b) : simplify

1/a = (c/bc) + (b/bc) : add numerators only, because the denominators match

1/a = (c + b)/bc : multiply both sides by a

1 = (a)[(c + b)/bc] : multiply both sides by the reciprocal of [(c + b)/bc] which is [bc/(b + c)]

1[bc/(b + c)] = a

a = bc/(b + c)

This will not work if c = -b, because then you would be dividing by zero.

Example: 1/2 - 1/3 = 1/6 a = 2, b = 3 c= 6

a = bc/(b + c) => 2 = (3 x 6)/(3 + 6) => 2 = 18/9 => 2 = 2.

Step-by-step explanation:

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Solnce55 [7]

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4 years ago

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0.73 as a fraction. please

Shalnov [3]

Answer:

73/100

Step-by-step explanation:

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3 years ago

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Brian spends

mariarad [96]

Answer:

Brian have £105 left.

Step-by-step explanation:

Given,

Amount earned by Brian per week = £168

Fraction spent on rent = 1/8

Amount spent on rent = 1/8 x 168

Amount spent on rent = £42

Fraction spent on food = 1/8

Amount spent on food = 1/8 x 168

Amount spent on food = £21

Amount left = Amount earned - amount spent on rent - amount spent on food

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Amount left = £105

Brian have £105 left.

I hope this helps you

5 0

3 years ago

The height of right circular cylinder P

Radda [10]

Answer:

A. 2

Step-by-step explanation:

The computation is shown below:

As we know that

The Volume of a right circular cylinder is

$V = \pi r^h\\\\$

Here r is the radius

And h is the height

Now it is mentioned that the height of the right circular cylinder P is double to the height of the right circular cylinder Q

Now let us assume h be the height of cylinder p

And, H be the height of cylinder Q

So the equation is

h = 2H ........(1)

Also

The radius of both the cylinders would be the similar length

we assume the r be the radius of both cylinders

Now

The Volume of cylinder Q = $V_Q = \pi r^2H$

And for P it is $V_p = \pi r^2 h$

Now substitute equation 1

$V_p = \pi r^2(2H)\\\\V_p= 2 \pi r^2hH\\\\V_p = 2(\pi r^2H)\\\\V_p = 2(V_Q)$

Hence, the correct option is A.

6 0

3 years ago

How do I figure this out? Y = - ⅙ x -1

astra-53 [7]

Now the fraction is your slope, it determines where your point goes, in this equation you would move up 6 times and move left once because your slope is -1/6. Now your numerator is the one that moves right if it's positive or left if if's negative. Your denominator is the one that moves up if it's positive and down if it's negative. So you're either going up 6 times and moving left once and if you're plotting two points then you move down 6 times and right once, it's basically the reverse. Now the number on the very right is your y-intercept it's always on the y-axis and that's how you start your line. from there you use the slope and plot the two other points and then you connect the points. That's how you do it, hope this helps.

3 0

3 years ago

Make B the subject of the relation : 1/a is equal to 1/b + c​

Make B the subject of the relation : 1/a is equal to 1/b + c