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Len [333]
3 years ago
6

BESTIES PLEASE HELP ASAP WILL GIVE POINTS AND BRAINLIEST. Express as a trinomial (2x-6) (x-4)

Mathematics
2 answers:
zaharov [31]3 years ago
4 0

Answer:

2x² - 14x + 24

Step-by-step explanation:

Use the FOIL method (First, Outside, Inside, Last).

First, multiply the first term of both parenthesis:

2x * x = 2x²

Next, multiply the outside terms of both parenthesis:

2x * -4 = -8x

Then, multiply the inside terms of both parenthesis:

-6 * x = -6x

Finally, multiply the last terms of both parenthesis:

-6 * -4 = 24

Combine like terms:

2x² - 8x - 6x + 24

2x² (-8x - 6x) + 24

2x² (-14x) + 24

2x² - 14x + 24 is your answer.

~

MissTica3 years ago
4 0

Answer:

2x^{2} -14x+24

Step-by-step explanation:

1. Distribute

(2x-6)(x-4)

2x(x-4)-6(x-4)

2. Distribute

2x(x-4)-6(x-4)      Distribute 2x(x-4)

2x^2-8x-6(x-4)

3. Distribute

2x^2-8x-6(x-4)       Distribute -6(x-4)

2x^2-8x-6x+24

4. Combine like terms

2x^2-8x-6x+24        Combine the like terms

2x^2-14x+24

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Suppose a football is kicked with an initial velocity of 82 ft/sec., at an angle of
satela [25.4K]

Answer:

The position P is:

P = 87\^x + 75\^y ft     <u><em> Remember that the position is a vector. Observe the attached image</em></u>

Step-by-step explanation:

The equation that describes the height as a function of time of an object that moves in a parabolic trajectory with an initial velocity s_0 is:

y(t) = y_0 + s_0t -16t ^ 2

Where y_0 is the initial height = 0 for this case

We know that the initial velocity is:

82 ft/sec at an angle of 58 ° with respect to the ground.

So:

s_0 = 82sin(58\°) ft/sec

s_0 = 69.54 ft/sec

Thus

y(t) = 69.54t -16t ^ 2

The height after 2 sec is:

y(2) = 69.54 (2) -16 (2) ^ 2

y(2) = 75\ ft

Then the equation that describes the horizontal position of the ball is

X(t) = X_0 + s_0t

Where

X_ 0 = 0 for this case

s_0 = 82cos(58\°) ft / sec

s_0 = 43.45 ft/sec

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X(t) = 43.45t

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X (2) = 43.45(2)\\\\X (2) = 87\ ft

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P = 87\^x + 75\^y ft

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Step-by-step explanation:

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