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S_A_V [24]
3 years ago
12

The 2nd term of an exponential sequence is 9 while the 4th term is 81.find the common ratio,the first term and the sum of the fi

rst five terms of the sequence
Mathematics
1 answer:
Thepotemich [5.8K]3 years ago
5 0

Answer:

second term: 9

4th term:81

(3rd \: term)^{2}  = 9 \times 81

=729

\sqrt{729}  = 27

3rd term=27

{9}^{2}  = a1x27 \\ 81 = 27a1

a1=3 the first term

81 = 3 \times {q}^{3}

{q}^{3}  = 27

q=3

s = 3x \frac{1 -  {3}^{5} }{1 - 3}  = 364.5

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