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aleksandrvk [35]
2 years ago
11

.prove that cos (90-A).sinA + sin(90 - A).cosA = 1 ​

Mathematics
1 answer:
pav-90 [236]2 years ago
4 0

Answer:

See Explanation

Step-by-step explanation:

cos (90-A).sinA + sin(90 - A).cosA = 1  \\  \\ LHS = cos (90-A).sinA + sin(90 - A).cosA \\  \\ = sinA.sinA + cosA.cosA\\  \\ = sin ^{2} A + cos^{2} A \\  \\  = 1 \\  \\=RHS\\\\ reason \\ cos (90- \theta) = sin \theta \\ sin (90- \theta) = cos \theta \\ sin ^{2}  \theta + cos^{2}  \theta = 1 \\  \\ thus \: proved \\

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Probability Definition in Math-

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brainly.com/question/11234923

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