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allochka39001 [22]
3 years ago
13

Find the value of the trig function indicated ​

Mathematics
1 answer:
Lera25 [3.4K]3 years ago
6 0

Answer:

\cos(\theta)=\frac{4}{5}

Step-by-step explanation:

Step 1:

Let us find the missing side. We know this is a <u>right triangle</u>, so we can use the pythagorean thereom to find the last side. Let us set 12 as variable <em>a</em>, 20 as variable <em>c</em>, and the unknown side as variable <em>b</em>.

a^2+b^2=c^2\\12^2_b^2=20^2\\b^2=400-144\\b^2=256\\b=\pm16

We do know that a <u>length can never be negative</u>, so the side <em>b</em> would be 16.

Step 2:

According to SOHCAHTOA, cosine is utilizes the adjacent and hypotenuse of the given angle theta. Let us write the equation:

\cos(\theta)=\frac{adjacent}{hypotenuse} \\\\\cos(\theta)=\frac{16}{20} \\\\\cos(\theta)=\frac{4}{5}

<em>I hope this helps! Let me know if you have any questions :)</em>

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(-1.5, 0), (0, -1)

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Answer:

z=\frac{0.340 -0.38}{\sqrt{\frac{0.38(1-0.38)}{830}}}=-2.374  

p_v =P(Z  

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Step-by-step explanation:

1) Data given and notation

n=830 represent the random sample taken

X=282 represent the people that regularly watch the TV station’s news program

\hat p=\frac{282}{830}=0.340 estimated proportion of people that regularly watch the TV station’s news program

p_o=0.38 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the proportion is less than 0.38:  

Null hypothesis:p\geq 0.38  

Alternative hypothesis:p < 0.38  

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.340 -0.38}{\sqrt{\frac{0.38(1-0.38)}{830}}}=-2.374  

4) Statistical decision  

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The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a left tailed test the p value would be:  

p_v =P(Z  

So the p value obtained was a very low value and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of people that regularly watch the TV station’s news program is significantly less than 0.38 .  

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