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Svet_ta [14]
3 years ago
10

Which of the following statements must be true about this diagram?

Mathematics
1 answer:
vaieri [72.5K]3 years ago
3 0

Answer:

A, C, D

Step-by-step explanation:

A, C, D

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Step-by-step explanation:


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cricket20 [7]
The answer is no solution because when you solve the equation

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3 years ago
If sine theta equals three over four, what are the values of cos θ and tan θ?
ankoles [38]

Answer:

Part 1) cos(\theta)=(+/-)\frac{\sqrt{7}}{4}

cosine theta equals plus or minus square root of seven over 4

Part 2) tan(\theta)=(+/-)\frac{3}{\sqrt{7}}

tangent theta equals plus or minus three over square root of seven

or

tan(\theta)=(+/-)3\frac{\sqrt{7}}{7}

tangent theta equals plus or minus three times square root of seven over seven

Step-by-step explanation:

we have that

The sine of angle theta is equal to

sin(\theta)=\frac{3}{4}

Is positive

therefore

The angle theta lie on the I Quadrant or in the II Quadrant

Part 1) Find the value of the cosine of angle theta

Remember that

sin^{2} (\theta)+cos^{2} (\theta)=1

we have

sin(\theta)=\frac{3}{4}

substitute and solve for cosine of angle theta

(\frac{3}{4})^{2}+cos^{2} (\theta)=1

cos^{2} (\theta)=1-(\frac{3}{4})^{2}

cos^{2} (\theta)=1-\frac{9}{16}

cos^{2} (\theta)=\frac{7}{16}

cos(\theta)=(+/-)\frac{\sqrt{7}}{4}

cosine theta equals plus or minus square root of seven over 4

Part 2) Find the value of tangent of angle theta

we know that

tan(\theta)=\frac{sin(\theta)}{cos(\theta)}

we have

sin(\theta)=\frac{3}{4}

cos(\theta)=(+/-)\frac{\sqrt{7}}{4}

substitute

tan(\theta)=\frac{\frac{3}{4}}{(+/-)\frac{\sqrt{7}}{4}}

tan(\theta)=(+/-)\frac{3}{\sqrt{7}}

tangent theta equals plus or minus three over square root of seven

Simplify

tan(\theta)=(+/-)3\frac{\sqrt{7}}{7}

tangent theta equals plus or minus three times square root of seven over seven

4 0
3 years ago
A rectangle has a perimeter of `52` cm. Its width is `9` cm.
Marizza181 [45]

Answer:

The length is 17 cm.

17+17+9+9 adds up to 52.

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3 years ago
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