X=width of a coccer pitch
2x-20=length of a soccer pitch
Area (rectangule)=length x width
We suggest this equation:
x(2x-20)=6000
2x²-20x=6000
2x²-20x-6000=0
x²-10x-3000=0
We solve this quadratic equation:
x=[10⁺₋√(100-4*1*-3000)]/2=[10⁺₋√(100+12000)]/2=
=(10⁺₋110)/2
we have two solutions:
x₁=(10-110)/2=-50, invalid solution.
x₂=(10+110)/2=60
x=60
2x-20=2(60)-20=120-20=100
Solution: the length is 100 m, and the width is 60 m.
To check:
Area=100 m*60 m=6000 m²
The twice of width is =2(60 m)=120 m,
20 m less than twice its width is: 120 m-20 m=100 m=the length.
Answer:
Step-by-step explanation:
4.30/40=$0.1075
Hope this helps :)
Answer:n= 1/3d - 2/3m
Step-by-step explanation:
d=2m+3n
Step 1: Flip the equation.
2m+3n=d
Step 2: Add -2m to both sides.
2m+3n+−2m=d+−2m
3n=d−2m
Step 3: Divide both sides by 3.
3n/3 = d-2m/3
Therefore
n= 1/3d - 2/3m
Hope this helps!
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maxtext75
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Answer:
n = d - 2m
3*
Step-by-step explanation:
First we want to get n alone on one side, so we should subtract 2m from both side;
d = 2m + 3n
3n = d - 2m
Now to get n by itself, we need to divide by 3 from both sides;
3n = d - 2m
n = d - 2m
3*
*Pretend there is a fraction bar between d - 2m and 3
Step-by-step explanation:
