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o-na [289]
3 years ago
11

(3m2 + 8 - 3) + (n + 3) Simplified

Mathematics
1 answer:
RUDIKE [14]3 years ago
3 0

Answer:

\boxed {3m^{2} + n + 8}

Step-by-step explanation:

Simplify the following expression:

(3m^{2} + 8 - 3) + (n + 3)

-Subtract 3 from 8:

(3m^{2} + 8 - 3) + (n + 3)

3m^{2}  + 5 + n + 3

-Add 5 and 3:

3m^{2}  + 5 + n + 3

\boxed {3m^{2} + n + 8}

Therefore, the final answer is 3m^{2} + n + 8.

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If BE = 2x + 2, BD = 5x – 3, and AE = 4x – 6, what are the values of x and AC?
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Answer: x=7 and AC = 44 unuts.

Step-by-step explanation:

We know that the diagonals of a parallelogram bisect each other. (i)

Here in parallelogram ABCD , AC and Bd are diagonals intersecting at E.

BE = 2x + 2, BD = 5x – 3, and AE = 4x – 6

Using (i)

BE=\dfrac{BD}{2}\\\\2x+2=\dfrac{5x-3}{2}\\\\ 2(2x+2)=5x-3\\\\ 4x+4= 5x-3\\\\ 5x-4x=4+3\\\\ x= 7

Now , AE = 4(7)-6 = 28-6 = 22

AC =2 AE = 2 (22) =44 units.

Hence, x=7 and AC = 44 unuts.

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