Cover job is indecent with the xo batial cap variable,
Answer:
Step-by-step explanation:
No but it is close. (4x +13x +10) factors into
(4x + 5)(x + 2)
So (x + 2) is a factor along with (4x + 5)
There are 10,000 total four-digit numbers (1000 through 9999).
Multiples of 2 end in 0, 2, 4, 6, and 8. There are 9*10*10*5 = 4500 four-digit multiples of 2.
Multiples of 5 end in 0 or 5. There are 9*10*10*2 = 1800 four-digit multiples of 5.
There is redundancy between the two sets of numbers, namely those that end in 0, which are both multiples of 2 and 5. There are 9*10*10*1 = 900 four-digit multiples of both 2 and 5.
Then there are 4500 + 1800 - 900 = 5400 total four-digit numbers that are either multiples of 2 or 5, which means the remaining 4600 numbers are neither multiples of 2 nor 5.
X = 13
( x + 4) / 51 = (2x - 7) / 57
585 = 45x
585/45 = 45x/45
x = 13
