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BabaBlast [244]
2 years ago
11

Find the Volume of a cone with radius r = 10 cm and height h = 24 cm. V=

Mathematics
1 answer:
den301095 [7]2 years ago
5 0

Answer:

≈2513.27

Step-by-step explanation:

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A rectangular piece of sheet metal has a length that is 6 in. less than twice the width. a square piece 3 in. on a side is cut f
m_a_m_a [10]
The original width would be 19 and the original length would be 32.

Let w be the width.  Then 2w-6 would be the length.  However, after cutting a 3-inch square from each corner, both the width and length left over to fold into a box would be 6 inches smaller; thus the dimensions would be w-6 and 2w-6-6 or 2w-12.  

Since the section cut out is 3 inches long, 3 will be the height of the box.

Volume is found by multiplying the length, width and height of the box; thus we have:

1014=(w-6)(2w-12)(3)

We multiply the binomials and have:
1014 = [w*2w-12*w-6*2w-6(-12)](3)
1014 = (2w²-12w-12w+72)(3)
1014 = (2w²-24w+72)(3)
1014 = 6w² - 72w + 216

When solving a quadratic equation, we want it set equal to 0.  Subtract 1014 from each side:

1014-1014 = 6w² - 72w + 216 - 1014
0 = 6w² - 72w - 798

We will use the quadratic formula to solve this:

w=\frac{-b\pm \sqrt{b^2-4ac}}{2a}
\\
\\=\frac{--72\pm \sqrt{(-72)^2-4(6)(-798)}}{2(6)}
\\
\\=\frac{72\pm \sqrt{5184--19152}}{12}
\\
\\=\frac{72\pm \sqrt{5184+19152}}{12}
\\
\\=\frac{72\pm \sqrt{24336}}{12}
\\
\\=\frac{72\pm 156}{12}
\\
\\=\frac{72+156}{12} \text{ or } \frac{72-156}{12}
\\
\\=\frac{228}{12} \text{ or } \frac{-84}{12}=19 \text{ or } -7

Since we cannot have a negative number for a measurement, 19 has to be the width; then 2(19)-6 = 32 would be the length.
4 0
3 years ago
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