I’m learning this to lol I think the answer is c because the absolute value is always positive right ? And the opposite of -0.89 would be positive 0.89 !
What is the interquartile range of the sequence 5,5,8,8,13,14,16,16,19,22,23,27,31 ?
Romashka-Z-Leto [24]
Answer:
The Interquartile range is 10.
Step-by-step explanation:
First, we will need to find the mean, the mean of this sequence is 16, you will now need to find quartile 1 and quartile 3. Quartile 1 is 13, and quartile 3 is 23. Lastly, subtract Quartile 3 and Quartile 1 will be the answer.
So, 23-13=10
The Answer will be 10, the interquartile range is 10.
Hope this helps!
Answer:
The solution to the inequality is all real values of n that respect the following condition: 2 < n < 6
Step-by-step explanation:
First, we need to separate the modulus from the rest of equation. So
3-l4-nl>1
-|4-n|>1-3
-|4-n|>-2
Multiplying everything by -1.
|4-n|<2
How to solve:
|x| < a means that -a<x<a
In this question:
|4-n|<2
-2<4-n<2
This means that:
4 - n > -2
-n > -6
Multiplying by -1
n < 6
And
4 - n < 2
-n < -2
Multiplying by 1
n > 2
Intersection:
Between n > 2 and n < 6 is 2 < n < 6
So the solution to the inequality is all real values of n that respect the following condition: 2 < n < 6
Y=9.25 (short answer but hope this helped u)
(2n+1)(2n-1)(n+5)
=(4n^2+2n-2n-1)(n+5)
=(4n^2-1)(n+5)
=4n^3-n+20n^2-5
4n^3+20n^2-n-5
