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Delicious77 [7]
2 years ago
8

What is the interquartile range of the sequence 5,5,8,8,13,14,16,16,19,22,23,27,31 ?

Mathematics
1 answer:
Romashka-Z-Leto [24]2 years ago
4 0

Answer:

The Interquartile range is 10.

Step-by-step explanation:

First, we will need to find the mean, the mean of this sequence is 16, you will now need to find quartile 1 and quartile 3. Quartile 1 is 13, and quartile 3 is 23. Lastly, subtract Quartile 3 and Quartile 1 will be the answer.

So, 23-13=10

The Answer will be 10, the interquartile range is 10.

Hope this helps!

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Which lists the steps in the correct order to find the median of this data set?
Fofino [41]

The median of the data set can be found as follows:

1. Put the numbers in order (from least to the greatest): 16, 18, 23, 24, 29, 30

2. Cross off high/low pairs: 16, 18, (23, 24,) 29, 30

3. Divide the sum by 2: (23 + 24)/2 = 23.5

<h3>What is the Median?</h3>

The median of a data set is the data value at the middle of the data set when it is ordered.

Steps to find the median of the data set, 24, 16, 23, 30, 18, 29:

1. Put the numbers in order (from least to the greatest)

16, 18, 23, 24, 29, 30

2. Cross off high/low pairs: 16, 18, (23, 24,) 29, 30

3. Divide the sum by 2: (23 + 24)/2 = 23.5

4

The median is therefore, 23.5.

Learn more about the median on:

brainly.com/question/26177250

3 0
2 years ago
2/5 as a decimal and percentage
erastova [34]
2/5 in a decimal form= 0.4

2/5 in a percentage form= 40%

Hope this Helps!
8 0
3 years ago
Read 2 more answers
What is the absolute value of -3?<br><br><br> 3<br> - 1/3 <br> -3<br> 1/3
Nezavi [6.7K]
The absolute value of -3 is 3 and -3 so both would be right
5 0
3 years ago
A new car is purchased for 22400 dollars. The value of the car depreciates at 11% per year. To the nearest tenth of a year , how
m_a_m_a [10]

Answer:

t= 12.9 years

Step-by-step explanation:

Value after t years = initial value ( 1 - r )^t

Where,

Value after t years= $5000

Initial value = $22,400

r= depreciation rate = 11%

t= length of time (years)

Value after t years = initial value ( 1 - r )^t

5000 = 22,400 ( 1 - 0.11)^t

5000 = 22,400(0.89)^t

Divide both sides by 22,400

(0.89)^t = 5000 / 22,400

(0.89)^t = 0.2232

Take the log of both sides

t log 0.89 = log 0.2232

t= log 0.2232 / log 0.89

= -0.6513 / -0.0506

= 12.87

t= 12.9 years

5 0
3 years ago
Mass of Weight(C)
Stolb23 [73]
I hope this helps
A.1,512
3 0
3 years ago
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