All categories

2 years ago

NEED ANSWER ASAP WILL GIVE BRAINLIEST FOR CORRECT ANSWER

Mathematics

2 answers:

Juliette [100K]2 years ago

4 0

Answer:

a person jumping on a trampoline

just olya [345]2 years ago

4 0

A person jumping on a trampoline.
This is because they would be going up and down and the graph wouldn’t stay the same as they are constantly moving.

You might be interested in

Match the solid figure to the appropriate formula.

Zinaida [17]

<span>1. A = 1/4s squared, square root of 3 equilateral triangle
2. A = bh rectangle
3. A = pi(r) squared circle area
4. A = 1/2 h (b1+ b2) trapezoid
5. C = pi(d) circle circumference
6. A = base x altitude parallelogram
7. A = 1/2(ap) regular polygon
8. A = 1/2(bh) triangle

</span><span>- regular polygon
- trapezoid
- parallelogram
- circle circumference
- equilateral triangle
- circle area</span>

4 0

3 years ago

Find f^-1(x) for f(x)=1/x^3 and state whether or not it is a function? (TIMED)

AnnZ [28]

Answer: d

Step-by-step explanation:

8 0

3 years ago

WILL GIVE BRAINLIEST FOR BEST ANSWER Maya wants to perform an experiment with a spinner labeled A, B, and C. The theoretical pro

nika2105 [10]

Answer: The answer is spinner B. There are 8 sections on the spinner and 4 of them have letter A, so P(A)= 1/2.

8 0

3 years ago

Read 2 more answers

Find the following integral

ololo11 [35]

There's nothing preventing us from computing one integral at a time:

$\displaystyle \int_0^{2-x} xyz \,\mathrm dz = \frac12xyz^2\bigg|_{z=0}^{z=2-x} \\\\ = \frac12xy(2-x)^2$

$\displaystyle \int_0^{1-x}\int_0^{2-x}xyz\,\mathrm dz\,\mathrm dy = \frac12\int_0^{1-x}xy(2-x)^2\,\mathrm dy \\\\ = \frac14xy^2(2-x)^2\bigg|_{y=0}^{y=1-x} \\\\= \frac14x(1-x)^2(2-x)^2$

$\displaystyle\int_0^1\int_0^{1-x}\int_0^{2-x}xyz\,\mathrm dz\,\mathrm dy\,\mathrm dx = \frac14\int_0^1x(1-x)^2(2-x)^2\,\mathrm dx$

Expand the integrand completely:

$x(1-x)^2(2-x)^2 = x^5-6x^4+13x^3-12x^2+4x$

Then

$\displaystyle\frac14\int_0^1x(1-x)^2(2-x)^2\,\mathrm dx = \left(\frac16x^6-\frac65x^5+\frac{13}4x^4-4x^3+2x^2\right)\bigg|_{x=0}^{x=1} \\\\ = \boxed{\frac{13}{240}}$

4 0

2 years ago

Number 11 and 12. Solve for x and y. Please and thank you.

vlada-n [284]

Answer:

11. x=18, y=5

12. x=17, y=9

Step-by-step explanation:

Use the angle property https://www.proprofs.com/quiz-school/story.php?title=angle-properties-parallel-lines (REFER TO THIS LINK)

4 0

1 year ago