First one has one solution
Second has infinite solutions
Third has no solutions.
We can find the number of extra clubs in the deck from the given probability, since the probability of drawing a diamond and a club is

but this would imply that

, which suggests we're taking 4 clubs out of the original deck and contradicts the problem statement that there are "too many clubs".
Perhaps the question is providing the probability of drawing a diamond, THEN a club, or vice versa. In that case, we have

and solving gives

, which makes more sense. Then the number of extra spades in the deck must be 2.
Answer:
Step-by-step explanation:
y=3|x|, shift right 8 units
y=3|x-8|, shift up 1 unit
y=3|x-8|+1
316 divided by 13= 24.3 gallons of water per square foot
Answer:
x = 10
Step-by-step explanation:
8x - 13 = 5x + 17 (DE = EF)
8x - 5x = 17 + 13
3x = 30
x = 10