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Korolek [52]
3 years ago
8

Write an equation in point-slope form for the line that passes through the point with the given slope. point: (-1, 5) and m=-4

Mathematics
2 answers:
Gelneren [198K]3 years ago
4 0

Answer:

Y - 5 = -4(x + 1)

Step-by-step explanation:

Hope this helps. Pls give brainliest.

Montano1993 [528]3 years ago
3 0

Answer:

y - 5 = -4(x + 1)

Step-by-step explanation:

The point-slope form is y - k = m(x - h).  The point is (h, k):  (-1, 5) and the slope is -4.

Here we have y - 5 = -4(x + 1)

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The television show CSI: Shoboygan has been successful for many years. That show recently had a share of 18, meaning that among
jeyben [28]

Answer:

(a) The value of P (None) is 0.062.

(b) The value of P(at least one) is 0.938.

(c) The value of P(at most one) is 0.253.

(d) The event is not unusual.

Step-by-step explanation:

Let <em>X</em> = number of households watching the show.

The probability of the random variable <em>x</em> is, P (X) = <em>p</em> = 0.18.

The sample selected for the survey is of size, <em>n</em> = 14

The random variable <em>X</em> follows a Binomial distribution with parameter <em>n</em> = 14 and <em>p</em> = 0.18.

The probability of a Binomial distribution is computed using the formula:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,...

(a)

Compute the probability that none of the households are tuned to CSI: Shoboygan as follows:

P(X=0)={14\choose 0}(0.18)^{0}(1-0.18)^{14-0}=1\times1\times0.06214=0.062

Thus, the value of P (None) is 0.062.

(b)

Compute the probability that at least one household is tuned to CSI: Shoboygan as follows:

P (X ≥ 1) = 1 - P (X < 1)

             = 1 - P (X = 0)

             =1-0.062\\=0.938

Thus, the value of P(at least one) is 0.938.

(c)

Compute the probability that at most one household is tuned to CSI: Shoboygan as follows:

P (X ≤ 1) = P (X = 0) + P (X = 1)

             ={14\choose 0}(0.18)^{0}(1-0.18)^{14-0}+{14\choose 1}(0.18)^{1}(1-0.18)^{14-1}\\=0.062+0.191\\=0.253

Thus, the value of P(at most one) is 0.253.

(d)

An event that has a very low probability of occurrence is known as an unusual event.

The probability of the event "at most one household is tuned to CSI: Shoboygan" is 0.253.

This probability value is not low.

Hence, the event is not unusual.

5 0
3 years ago
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Sergeeva-Olga [200]

Two brownies among three friends.

3/2 is 1.5

So 1.5 for the first friend, 1.5 for another friend, and 1.5 for the other friend.

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2 years ago
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Answer:

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Step-by-step explanation:

8 3/15 - 4 3/15 the 3/15 cancel each other out so then there is only 8-4 which is 4

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B is the answer because you have to math it
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