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zalisa [80]
3 years ago
11

What is the answer plz?

Mathematics
2 answers:
Studentka2010 [4]3 years ago
8 0

Answer:

read the explanation

Step-by-step explanation:

the first one is positive 24 and the second one is -2

Setler79 [48]3 years ago
6 0

Answer:

-6 x (-4) = 24

-8/ 4 = -2

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egoroff_w [7]
So for A Write all numerators above the least common denominator Add the numbers
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7 0
3 years ago
What are the solutions to the system of equations? y=x2−7x+12y=−x+7
kap26 [50]

Answer:

x = 1, y = 6

or

x = 5, y = 2.

Step-by-step explanation:

y=x2−7x+12

y=−x+7

Substitute for y in the first equation:

- x + 7 = x^2 - 7x + 12

x^2 - 7x + x + 12 - 7 = 0

x^2 - 6x + 5 = 0

(x - 1)(x - 5) = 0

x = 1, 5.

When x = 1, y = -1 + 7 = 6.

when x = 5, y = -5+7 = 2.

3 0
2 years ago
The National Center for Education Statistics surveyed a random sample of 4400 college graduates about the lengths of time requir
Paha777 [63]

Answer:

95​% confidence interval for the mean time required to earn a bachelor’s degree by all college students is [5.10 years , 5.20 years].

Step-by-step explanation:

We are given that the National Center for Education Statistics surveyed a random sample of 4400 college graduates about the lengths of time required to earn their bachelor’s degrees. The mean was 5.15 years and the standard deviation was 1.68 years respectively.

Firstly, the pivotal quantity for 95% confidence interval for the population mean is given by;

                              P.Q. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean time = 5.15 years

            \sigma = sample standard deviation = 1.68 years

            n = sample of college graduates = 4400

            \mu = population mean time

<em>Here for constructing 95% confidence interval we have used One-sample z test statistics although we are given sample standard deviation because the sample size is very large so at large sample values t distribution also follows normal.</em>

<u>So, 95% confidence interval for the population mean, </u>\mu<u> is ;</u>

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5%

                                               level of significance are -1.96 & 1.96}  

P(-1.96 < \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } < 1.96) = 0.95

P( -1.96 \times {\frac{\sigma}{\sqrt{n} } } < {\bar X-\mu} < 1.96 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.95

P( \bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } } < \mu < \bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } } ) = 0.95

<u>95% confidence interval for</u> \mu = [ \bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } } , \bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } } ]

                                              = [ 5.15-1.96 \times {\frac{1.68}{\sqrt{4400} } } , 5.15+1.96 \times {\frac{1.68}{\sqrt{4400} } } ]

                                             = [5.10 , 5.20]

Therefore, 95​% confidence interval for the mean time required to earn a bachelor’s degree by all college students is [5.10 years , 5.20 years].

8 0
3 years ago
Kimora’s cell phone company charges her $35 a month for phone service plus $.05 for each text message sent. How many text messag
professor190 [17]

Given that Kimora’s cell phone company charges her $35 a month for phone service plus $.05 for each text message sent.

Kimora's cell phone bill for one month is $52.

We need to determine the number of text messages Kimora sent for one month.

Also, we need to write and equation and solve it.

<u>The equation:</u>

Let x denote the number of text messages Kimora sent for one month.

Thus, the equation is given by

35+0.05x=52

Therefore, the equation for the number of text messages Kimora sent for one month is 35+0.05x=52

<u>Solving the equation:</u>

We need to solve the equation 35+0.05x=52

Subtracting both sides of the equation by 35, we get;

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Dividing both sides of the equation by 0.05, we get;

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Ainat [17]

Answer:

Y - 6x = - 20

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Y = 6x + c

Substituting the value of x and y

4 = 24 + c

Subtracting 24 from both sides

C = - 20

Y = 6x - 20

Subtracting 6x from both sides

Y - 6x =- 20

7 0
3 years ago
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