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3 years ago

Roberto has run the first 18 miles of a race, which means he is 72% finished. How long is the race

Mathematics

1 answer:

Mamont248 [21]3 years ago

6 0

Answer:

25 miles

Step-by-step explanation:

18 ÷ 72% =

18 ÷ (72 ÷ 100) =

(100 × 18) ÷ 72 =

1,800 ÷ 72 =

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Options of Answer

Naya [18.7K]

Answer:

D) 18 bags of chips and 6 jars of salsa

Step-by-step explanation:

Given : The networking organization you joined is throwing a party. You are in charge of buying the chips, which cost $2.50 per bag and salsa, which costs $4 per jar. The chips & salsa budget you are given totals $60.

Inequality: $2.5x+4y$ ≤ $60$

Solution :

x represents chips

y represents salsa

Option a: 10 bags of chips and 2 jars of salsa

so, x = 10 and y =2

Putting values in inequality

$2.5(10)+4(2)$ ≤ $60$

$25+8$ ≤ $60$

$33$ ≤ $60$

Hence it is correct.

Option c : 14 bags of chips and 5 jars of salsa

so, x = 14 and y =5

Putting values in inequality

$2.5(10)+4(2)$ ≤ $60$

$50+8$ ≤ $60$

$58$ ≤ $60$

Hence it is correct.

Option c : 14 bags of chips and 5 jars of salsa

so, x = 14 and y =5

Putting values in inequality

$2.5(14)+4(5)$ ≤ $60$

$35+20$ ≤ $60$

$55$ ≤ $60$

Hence it is correct.

Option d :18 bags of chips and 6 jars of salsa

so, x = 18 and y =6

Putting values in inequality

$2.5(18)+4(6)$ ≤ $60$

$45+24$ ≤ $60$

$69\geq 60$

Hence it is not correct since it violates the inequality

5 0

3 years ago

2. Store A sells 10 donuts for $9. Store B sells 15 donuts for $12. Which is the better buy? Justify

Alenkinab [10]

Store B is better. Let’s say you get 30 donuts from each store, you would multiply 10 times 3= 30 donuts and $9 times 3= 27.
Now for the other store 15 times 2=30 and $12 times 2=24

4 0

3 years ago

Figure ABCD was translated and resulted in image A'B'C'D'.

zimovet [89]

Step-by-step explanation:

+) Polygons ABCD has: A(-7;4); B(-5;7); C(-3;4); D(-5; 1)

+) Polygons A'B'C'D' has: A'(-9;0); B'(-7;3); C'(-5;0); D'(-7;-3)

The side lengths of ABCD:

$AB = \sqrt{[-7-(-5)]^{2}+(4-7)^{2} } = \sqrt{13}$

$BC = \sqrt{[-3-(-5)]^{2}+(7-4)^{2} } =\sqrt{13}$

$CD = \sqrt{[-5-(-3)]^{2}+(1-4)^{2} } =\sqrt{13}$

$DA = \sqrt{[-7-(-5)]^{2}+(4-1)^{2} } =\sqrt{13}$

The side lengths of A'B'C'D':

$A'B' = \sqrt{[-7-(-9)]^{2}+(3-0)^{2} } = \sqrt{13}$

$B'C' = \sqrt{[-5-(-7)]^{2}+(0-3)^{2} } =\sqrt{13}$

$C'D' = \sqrt{[-7-(-5)]^{2}+(-3-0)^{2} } =\sqrt{13}$

$D'A' = \sqrt{[-9-(-7)]^{2}+[0-(-3)]^{2} } =\sqrt{13}$

So that side lengths of ABCD equal to those of A'B'C'D'.

However, this is not enough to said that they are congruent polygons, as 2 polygons are congruent when they have all corresponding sides and interior angles are congruent.

ABCD and A'B'C'D' have all corresponding sides congruent.

=> <em>So that "all corresponding interior angles are congruent" must be true for them to be congruent polygons</em>

7 0

3 years ago

Collectively, what are the interest costs and other fees for using a credit card called?

zavuch27 [327]

Answer:C

Step-by-step explanation:

answer is c

5 0

3 years ago

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