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Sergio039 [100]
3 years ago
8

Options of Answer

Mathematics
1 answer:
Naya [18.7K]3 years ago
5 0

Answer:

D) 18 bags of chips and 6 jars of salsa

Step-by-step explanation:

Given :  The networking organization you joined is throwing a party. You are in charge of buying the chips, which cost $2.50 per bag and salsa, which costs $4 per jar. The chips & salsa budget you are given totals $60.

Inequality: 2.5x+4y ≤ 60

Solution :

x represents chips

y represents salsa

Option a: 10 bags of chips and 2 jars of salsa

so, x = 10 and y =2

Putting values in inequality

2.5(10)+4(2) ≤60

25+8 ≤60

33≤60

Hence it is correct.

Option c : 14 bags of chips and 5 jars of salsa

so, x = 14 and y =5

Putting values in inequality

2.5(10)+4(2)≤60

50+8≤60

58≤60

Hence it is correct.

Option c : 14 bags of chips and 5 jars of salsa

so, x = 14 and y =5

Putting values in inequality

2.5(14)+4(5)≤60

35+20≤60

55≤60

Hence it is correct.

Option d :18 bags of chips and 6 jars of salsa

so, x = 18 and y =6

Putting values in inequality

2.5(18)+4(6)≤60

45+24≤60

69\geq 60

Hence it is not correct since it violates the inequality

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John invested his inheritance of $12000 in 3 different funds part in a money market fund paying 3% interest annually Parton monu
Leokris [45]

Answer:

John invested $2,000 in money-market fund, $3,000 in municipal bonds, and $7,000 in mutual funds.

Step-by-step explanation:

Note: This question is not complete. The complete question is therefore provided before answering the question as follows:

John invested his inheritance of $12,000 in three different funds: part in a money-market fund paying 3% interest annually; part in municipal bonds paying 4% annually; and the rest in mutual funds paying 7% annually. John invested $4,000 more in mutual funds than he invested in municipal bonds. The total interest earned in one year was $670. How much did he invest in each type of fund?

The explanation of the answer is now given as follows:

Let a, b and c represent the amount invested in money-market fund, municipal bonds and mutual funds respectively. Therefore, the sum of the three principal amounts can be represented as follows:

a + b + c = 12,000 ……………………….. (1)

Since John invested $4,000 more in mutual funds than he invested in municipal bonds, we have:

c = b + 4,000 ……………………………. (2)

The total amount of interest earned from each fund can be represented as follows:

0.03a + 0.04b + 0.07c = 670 ………………. (3)

Substituting equation (2) into equation (1), we have:

a + b + b + 4,000 = 12,000

a + 2b = 12,000 – 4,000

a + 2b = 8,000

a = 8,000 – 2b ……………………….. (4)

Also, substituting equation (2) into equation (3), we have:

0.03a + 0.04b + 0.07(b + 4,000) = 670

0.03a + 0.04b + 0.07b + 280 = 670

0.03a + 0.04b + 0.07b 0 = 670 – 280

0.03a + 0.11b = 390 ,,,,,,,,,,,,,,,,,,,,,, (5)

Substituting equation (4) into equation (5) and solve for b, we have:

0.03(8,000 – 2b) + 0.11b = 390

240 – 0.06b + 0.11b = 390

240 + 0.05b = 390

0.05b = 390 – 240

0.05b = 150

b = 150 / 0.05

b = 3,000

Substituting b = 3,000 into equation (2), we have:

c = 3,000 + 4,000

c = 7,000

Also, substituting b = 3,000 into equation (4), we have:

a = 8,000 – (2 * 3,000)

a = 8,000 – 6,000

a = 2,000

Therefore, John invested $2,000 in money-market fund, $3,000 in municipal bonds, and $7,000 in mutual funds.

8 0
3 years ago
What is a21 of the arithmetic sequence for which a7=−19 and a10=−28? A. -35 B. 35 C. -58 D. -61
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Answer:

a21 = -61

Step-by-step explanation:

a_{n}=a_{1}+(n-1)d

-19=a_{1}+(7-1)d

-28=a_{1}+(10-1)d (subtract to eliminate a₁)

9 = -3d

d = -3

-19 = a₁ + (6)(-3)

-1 = a

a21 = -1 + (21 - 1)(-3)

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The answer to this problem is  2/5
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James determined that these two expressions were equivalent expressions using the values of x = 4 and x = 6. Which statements ar
GarryVolchara [31]

Answer:

When x=2, both expressions have a value of 18.

The expressions have equivalent values for any value of x.

The expressions have equivalent values if x=8

Step-by-step explanation:

James determined that these two expressions were equivalent expressions using the values of x = 4 and x = 6. Which statements are true? Check all that apply. 7 x + 4 and 3 x + 5 + 4 x minus 1

When x = 2, both expressions have a value of 18.

7x + 4

= 7(2) + 4

= 14 + 4

= 18

3x + 5 + 4x - 1

3(2) + 5 + 4(2) - 1

6 + 5 + 8 - 1

= 18

The expressions are only equivalent for x = 4 and x = 6.

• This is not true because the expression is also equivalent for x = 2

The expressions are only equivalent when evaluated with even values.

When x = 1

7x + 4

7(1) + 4

= 7 + 4

= 11

3x + 5 + 4x - 1

3(1) + 5 + 4(1) - 1

3 + 5 + 4 - 1

= 11

The expressions have equivalent values for any value of x.

Yes, it has an equivalent value at any value of x

The expressions should have been evaluated with one odd value and one even value.

When x = 0, the first expression has a value of 4 and the second expression has a value of 5.

7x + 4

7(0) + 4

= 0 + 4

= 4

3x + 5 + 4x - 1

3(0) + 5 + 4(0) - 1

0 + 5 + 0 -1

= 4

The expressions have equivalent values if x = 8.

7x + 4

7(8) + 4

56 + 4

= 60

3x + 5 + 4x - 1

3(8) + 5 + 4(8) - 1

24 + 5 + 32 - 1

= 60

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3 years ago
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