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2 years ago

I need help! please!

Mathematics

1 answer:

mamaluj [8]2 years ago

7 0

Answer:

$- \frac{1}{3}$

Step-by-step explanation:

The only thing important in this question in the original equation is the slope, which is 3, the multiplyer for x. To find the opposite slope follow the steps below.

The first step is to make the original slope into a fraction.

$\frac{3}{1}$

Then flip the numerator and denominator.

$\frac{1}{3}$

Now multiply this value by -1.

$\frac{1}{3} \times ( - 1) = - \frac{1}{3}$

There is the opposite slope of 3.

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Since angle B is the largest angle, AC is the side

Vesna [10]

Answer:

AC is the largest side

Step-by-step explanation:

The longest side of a triangle is opposite the largest angle, and the shortest side is opposite the smallest angle.

6 0

3 years ago

Read 2 more answers

A _______ represents the idea of "if and only if." Its symbol is a double arrow, left right arrow↔.

Bond [772]

Answer:

A bi-conditional statement represents the idea of "if and only if." Its symbol is a $\leftrightarrow$ .

Step-by-step explanation:

We have been given an incomplete sentence. We are supposed to fill in the given blank.

A _______ represents the idea of "if and only if." Its symbol is a $\leftrightarrow$ .

We know that "if and only if" stands for bi-conditional statement, which represents either both statements are true or both are false.

The symbol $\leftrightarrow$ represent a bi-conditional statement.

Therefore, our complete statement would be: A bi-conditional statement represents the idea of "if and only if." Its symbol is a $\leftrightarrow$ .

4 0

3 years ago

Can someone help me with this please??

Llana [10]

Answer:

(x-5)*(x+5)

Step-by-step explanation:

= x^2 + 5x - 25 - 5x

= x^2 +5x - 5x -25

because +5x - 5x = 0 so

= x^2 + 0 - 25

= x^2 - 25

25 can be written as 5^2

= x^2 - 5^2

we know that a^2 - b^2 = (a-b) * (a+b)

so x^2 - 5^2

= (x-5) * (x+5)

Hope this help you :3

4 0

3 years ago

Express the complex number in trigonometric form. 3 - 3i radians pls

belka [17]

$\bf \begin{array}{llll}
3&-&3i\\
\uparrow &&\uparrow \\
a&&b
\end{array}\qquad 
\begin{cases}
r=\sqrt{a^2+b^2}\\
\theta=tan^{-1}\left( \frac{b}{a} \right)
\end{cases}\\\\
-----------------------------\\\\
r=\sqrt{3^2+3^2}\implies r=\sqrt{18}\implies r=3\sqrt{2}
\\\\\\
tan(\theta)=\cfrac{3}{3}\implies tan(\theta)=1\implies \measuredangle \theta=tan^{-1}(1)
\\\\\\
\measuredangle \theta=\frac{\pi }{4}\impliedby \textit{reference angle}$

now, b is -3, and a is 3
or in rectangular if you wish, y = -3 and x = 3.... on what quadrant is "y" negative and "x" positive? well, the 4th quadrant
so, using our reference angle, that'd be $\bf \cfrac{7\pi }{4}\quad or \quad -\cfrac{\pi }{4}$

so, let's use the first one

$\bf (3,3i)\implies 
\begin{array}{llll}
r[cos(\theta)+i\ sin(\theta)]\\\\
3\sqrt{2}\left[ cos\left( \frac{7\pi }{4} \right)+i\ sin\left( \frac{7\pi }{4} \right) \right]
\end{array}$

5 0

3 years ago

PLEASE HELP!!!!!! :)

trasher [3.6K]

Answer:

C: -19

6 to 7=13

7 to 8=15

8 to 9=17

9 to 10=19

3 0

3 years ago