Answer:
We need 92.3 grams of sodium azide
Explanation:
Step 1: Data given
Mass of nitrogen gas = 59.6 grams
Molar mass of nitrogen gas = 28.0 g/mol
Molar mass of sodium azide = 65.0 g/mol
Step 2: The balanced equation
2NaN3 → 2Na + 3N2
Step 3: Calculate moles nitrogen gas
Moles N2 = mass N2 / molar mass N2
Moles N2 = 59.6 grams/ 28.0 g/mol
Moles N2 = 2.13 moles
Step 4: Calculate moles NaN3
for 2 moles NaN3 we'll have 2 moles Na and 3 moles N2
For 2.13 moles N2 we need 2/3* 2.13 = 1.42 moles NaN3
Step 5: Calculate mass NaN3
Mass NaN3 = Moles NaN3 * molar mass NaN3
Mass NaN3 = 1.42 moles * 65.0 g/mol
Mass NaN3 = 92.3 grams
We need 92.3 grams of sodium azide
Answer:
mass of methanol = 519.3 g
Explanation:
Given data:
molecules of CH3OH = 9.77 × 10∧ 24
mass in gram = ?
Solution:
First of all we will calculate the number of moles:
(9.77 × 10∧ 24) × 1 mol / 6.02 × 10∧23 = 16.229 moles
Now we will calculate the mass in gram:
Formula:
number of moles = mass/ molar mass
16.229 mole = mass / 32 g/mol
mass = 16.229 mol × 32 g/ mol
mass = 519.3 g
Simple method:
molar mass of CH3OH is 32 g so according to Avogadro number,
32 g of CH3OH = 6.02 × 10∧23 molecules
9.77*10^24 molecules will be equal to
(32 g of CH3OH / 6.02 × 10∧23 molecules) × 9.77*10^24 molecules
= 5.136 × 10∧-23 g/molecules × 9.77*10^24 molecules
= 519.3 g
The concentration in ppm = 125,000 ppm
<h3>Further explanation</h3>
The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight / volume,), molarity, molality, parts per million (ppm) or mole fraction. The concentration shows the amount of solute in a unit of the amount of solvent.
ppm or parts per million (ppm) :
For water solvent = 1 ppm ⇒ 1 mg/L(1 kg=1 L,ρ water=1 kg/L)
In percent mass = 1 ppm ⇒ 1 mg/ 1 kg
Solution contains 0.25 kg of lead in 2 kg of water :
Solvent = water = 2 kg = 2 L
Solute= lead=0.25 kg=250000 mg
So the concentration in ppm :
Answer:
D.
Explanation:
Adding more gas particles to a set volume will increase the number of collisions, thus increasing collision force and pressure.