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2 years ago

Which compound in each pair is more soluble in water?(b) Calcium phosphate or magnesium phosphate

Chemistry

1 answer:

Sidana [21]2 years ago

6 0

larger is the value of $Ksp$ the higher will the solubility of solid in water.

What is called compound?

In chemistry, a compound is a substance made up of two or more different chemical elements combined in a fixed ratio.
When the elements come together, they react with each other and form chemical bonds that are difficult to break.
These bonds form as a result of sharing or exchanging electrons between atoms.

The equation for the dissociation of a solid MX in water is given below

MX(s) ⇄ Mⁿ⁺(aq) + Xⁿ⁻ (aq)

Assume s be the solubility of MX in pure water, then the equilibrium concentrations of ions are

[ Mⁿ⁺] = s

[ Xⁿ⁻ ] = s

The expression for the solubility product constant ( $Ksp$ ) is as follows

$Ksp$ = [ Mⁿ⁺] [ Xⁿ⁻ ]

= s²

That is, larger is the value of $Ksp$ the higher will the solubility of solid in water.

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A compound of a transition metal and iodine is 56.7% metal by mass.How many grams of the metal can be obtained from 630 g of thi

erma4kov [3.2K]

Answer:

357 g of the transition metal are present in 630 grams of the compound of the transition metal and iodine

Explanation:

In any sample of the compound, the percentage by mass of the transition metal is 56.7%. This means that for a 100 g sample of the compound, 56.7 g is the metal while the remaining mass, 43.3 g is iodine.

Given mass of sample compound = 630 g

Calculating the mass of iodine present involves multiplying the percentage by mass composition of the metal by the mass of the given sample;

56.7 % = 56.7/100 = 0.567

Mass of transition metal = 0.567 * 630 = 357.21 g

Therefore, the mass of the transition metal present in 630 g of the compound is approximately 357 g

4 0

3 years ago

Sample A: 300 mL of 1M sodium chloride

yarga [219]

Answer:

sample B contains the larger density

Explanation:

Given;

volume of sample A, V = 300 mL = 0.3 L

Molarity of sample A, C = 1 M

volume of sample B, V = 145 mL = 0.145 L

Molarity of sample B, C = 1.5 M

molecular mass of sodium chloride, Nacl = 23 + 35.5 = 58.5 g/mol

Molarity is given as;

$C = \frac{moles \ of \ solute, \ mol}{liters \ of \ solvent} \\\\Moles \ of \ solute \ for \ sample \ A = 1 \times 0.3 = 0.3 \ mol\\\\Moles \ of \ solute \ for \ sample \ B = 1.5 \times 0.145 = 0.2175 \ mol$

The reacting mass for sample A = 0.3mol x 58.5 g/mol = 17.55 g

The reacting mass for sample B = 0.2175 mol x 58.5 g/mol = 12.72 g

The density of sample A $= \frac{mass}{volume} = \frac{17.55}{0.3} = 58.5 \ g/L$

The density of sample B $= \frac{mass}{volume} = \frac{12.72}{0.145} = 87.72 \ g/L$

Therefore, sample B contains the larger density

5 0

3 years ago

The compound ncl3 is nitrogen trichloride, but alcl3 is simply aluminum chloride. why

AveGali [126]

The answer to this question would be:
NCl3 is a molecular compound (two or more nonmetals), and therefore in its name prefixes indicate the number of each type of atom. so NCl3 is nitrogen trichloride.
The compound AlCl3 is an ionic compound (metal and nonmetal), and therefore does not require prefixes. so AlCl3 is aluminum chloride.

Both of nitrogen and chlorine is nonmetal, but aluminum is metal. Metal with nonmetal will make an ionic compound that doesn't need prefixes.

5 0

4 years ago

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RUDIKE [14]

Answer:

Explanation:

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4 0

3 years ago

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Select the correct answer.