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3 years ago

13

Graph each function (equation) by making a table y = |2x| + 1please help

1 answer:

Svetradugi [14.3K]3 years ago

8 0

Answer:

the table:

x | y

-2 | 5

-1 | 3

0 | 1

1 | 3

2 | 5

for the graph: go up from the middle point, then right then up by two and repeat on the other side as well, should look something like this

<h2> ( up one, go left, up 2) ∨ (up one, go right up two)</h2>

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For the given central angle, determine the distance traveled along the unit circle from the point (1,0). 57

aliina [53]

Answer: (a)- $0.99\ \text{units}$

Step-by-step explanation:

Given

Central angle is $57^{\circ}$

The radius of the unit circle is $1\ \text{unit}$

Arc length is given by

$\Rightarrow l=\dfrac{\theta}{360^{\circ}}\times 2\pi r$

Put the values

$\Rightarrow l=\dfrac{57}{360}\times 2\pi \cdot1\\\\\Rightarrow l=0.99\ \text{units}$

6 0

3 years ago

I know you want to answer this question.

Alik [6]

Answer:

D. x = 3

Step-by-step explanation:

$\frac{1}{2} ^{x-4}$ - 3 = $4^{x-3}$ - 2

First, convert $4^{x-3}$ to base 2:

$4^{x-3}$ = $(2^{2})^{x-3}$

$\frac{1}{2} ^{x-4}$ - 3 = $(2^{2})^{x-3}$ - 2

Next, convert $\frac{1}{2} ^{x-4}$ to base 2:

$\frac{1}{2} ^{x-4}$ = $(2^{-1})^{x-4}$

$(2^{-1})^{x-4}$ - 3 = $(2^{2})^{x-3}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$(2^{-1})^{x-4}$ = $2^{-1*(x-4)}$

$2^{-1*(x-4)}$ - 3 = $(2^{2})^{x-3}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$(2^{2})^{x-3}$ = $2^{2(x-3)}$

$2^{-1*(x-4)}$ - 3 = $2^{2(x-3)}$ - 2

Apply exponent rule: $a^{b+c}$ = $a^{b}$ $a^{c}$ :

$2^{-1(x-4)}$ = $2^{-1x}$ * $2^{4}$ , $2^{2(x-3)}$ = $2^{2x}$ * $2^{-6}$

$2^{-1 * x}$ * $2^{4}$ - 3 = $2^{2x}$ * $2^{-6}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$2^{-1x}$ = $(2^{x})^{-1}$ , $2^{2x}$ = $(2^{x})^{2}$

$(2^{x})^{-1}$ * $2^{4}$ - 3 = $(2^{x})^{2}$ * $2^{-6}$ - 2

Rewrite the equation with $2^{x} = u$ :

$(u)^{-1}$ * $2^{4}$ - 3 = $(u)^{2}$ * $2^{-6}$ - 2

Solve $u^{-1}$ * $2^{4}$ - 3 = $u^{2}$ * $2^{-6}$ - 2:

$u^{-1}$ * $2^{4}$ - 3 = $u^{2}$ * $2^{-6}$ - 2

Refine:

$\frac{16}{u}$ - 3 = $\frac{1}{64}$ $u^{2}$ - 2

Add 3 to both sides:

$\frac{16}{u}$ - 3 + 3 = $\frac{1}{64}$ $u^{2}$ - 2 + 3

Simplify:

$\frac{16}{u}$ = $\frac{1}{64}$ $u^{2}$ + 1

Multiply by the Least Common Multiplier (64u):

$\frac{16}{u}$ * 64u = $\frac{1}{64}$ $u^{2}$ + 1 * 64u

Simplify:

$\frac{16}{u}$ * 64u = $\frac{1}{64}$ $u^{2}$ + 1 * 64u

Simplify $\frac{16}{u}$ * 64u:

1024

Simplify $\frac{1}{64}$ $u^{2}$ * 64u:

$u^{3}$

Substitute:

1024 = $u^{3}$ + 64u

Solve for u:

u = 8

Substitute back u = $2^{x}$ :

8 = $2^{x}$

Solve for x:

x = 3

4 0

3 years ago

The angle measures of triangle QRS are given:

Trava [24]

Answer:

x = 15°

Step-by-step explanation:

(5x-15) + 75 + 3x = 180

8x + 60 = 180

8x = 120

x = 15°

7 0

3 years ago

Use powers to rewrite these problems: Example: 5 x 5 = 52

jeyben [28]

Answer:

<u>Problem A</u>

5 * 5 * x * x * x

$5^2*x^3$

<u>Problem B</u>

8 * 8 * 8

$8^3$

<u>Problem C</u>

4 * 4 * 4 * x * x * x * x

$4^3*x^4$

5 0

2 years ago

andrezito [222]

Answer:

Step-by-step explanation:

5 0

2 years ago