Answer:
Area of Mrs. Rockwell's lot is equal to the area of Mr. Brown's lot
Step-by-step explanation:
We can suppose the dimensions of Mrs. Rockwell's lot to be:
Length = x
Width = y
Then, we can write the dimensions of Mr. Brown's lot as:
Length = half as long as Mrs. Rockwell's lot
Length = 0.5x
Width = twice as wide as Mrs. Rockwell's lot
Width = 2y
Area of Mrs. Rockwell's lot = Length * Width
= x*y
Area of Mrs. Rockwell's lot = xy
Area of Mr. Brown's lot = 0.5x*2y
Area of Mr. Brown's lot = xy
<u>Area of Mrs. Rockwell's lot </u><u>is equal</u><u> to the area of Mr. Brown's lot, as calculated above</u>.
12 m
<span><span>10π</span><span>40π</span></span><span> = </span><span><span>62</span><span>x2</span></span>
x = 12
<span>When </span>circles<span> have the same </span>central<span> angle measure, the </span>ratio<span> of measure of the </span>sectors<span> is the same as the </span>ratio<span> of the radii </span>squared<span>.</span>
It is 74 because 10/10 equal 1 . 73+1=74
Answer:
The choose D (2, –1)
2x-3y=4 —> 3y=2X-4 —> y= 2/3x – 4/3
y=mx+b —> So ; m= 2/3 , b= - 4/3
y-intercept :(0, -4/3)
0=2/3x –4/3 —> 2/3x = 4/3 —> X=2
x-intercept ; (2,0)
By drawing a straight line from point 2 on the x-axis and point -4/3 on the y-axis, the points that are on the axis have been extracted, but the point (2,-1) is not on the axis . :)
I hope it helped you ^_^
Question
<em>Which equation shows the Identity Property of Multiplication?</em>
<em>Answer</em>
<em>There are four properties involving multiplication that will help make problems easier to solve. They are the commutative, associative, multiplicative identity and distributive properties. Multiplicative identity property: The product of any number and one is that number.</em>
D.) 45*1=45
Hope this helps!
