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lys-0071 [83]
3 years ago
14

Triangle ABC has vertices A(-2, 3), B(0, 3), and C(-1,-1). Find the coordinates of the image after a reflection over the

Mathematics
1 answer:
motikmotik3 years ago
8 0

<u>Given</u>:

Given that the triangle ABC has vertices A(-2,3), B(0,3) and C(-1,-1).

We need to determine the coordinates of the image after a reflection over the x - axis.

Let A'B'C' denote the coordinates of the triangle after a reflection over the x - axis.

<u>Coordinates of the point A':</u>

The general rule to reflect the coordinate across the x - axis is given by

(x,y)\rightarrow (x,-y)

Substituting the point A(-2,3), we get;

(-2,3)\rightarrow (-2,-3)

Thus, the coordinates of the point A' is (-2,-3)

<u>Coordinates of the point B':</u>

The general rule to reflect the coordinate across the x - axis is given by

(x,y)\rightarrow (x,-y)

Substituting the point B(0,3), we get;

(0,3)\rightarrow (0,-3)

Thus, the coordinates of the point B' is (0,-3)

<u>Coordinates of the point C':</u>

The general rule to reflect the coordinate across the x - axis is given by

(x,y)\rightarrow (x,-y)

Substituting the point C(-1,-1), we get;

(-1,-1)\rightarrow (-1,1)

Thus, the coordinates of the point C' is (-1,1)

Hence, the coordinates of the image after a reflection over the x - axis is A'(-2,-3), B(0,-3) and C(-1,1)

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The length of a rectangle is 88 inches longer than the width. If the perimeter of the rectangle is 7272 ​inches, find the measur
tresset_1 [31]

The perimeter (IP) of a rectangle is

P = 2(length + width)

let width = w then length = w + 88

P = 2(w+w+88) = 2(2w+88) = 4w+176

Thus P = 4w+176 = 7272

hence 4w = 7272 - 176 = 7096

so w = 7096/4 = 1774

width = 1774 inches and length = w+88 = 1774+88 = 1862 inches




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