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lys-0071 [83]
4 years ago
14

Triangle ABC has vertices A(-2, 3), B(0, 3), and C(-1,-1). Find the coordinates of the image after a reflection over the

Mathematics
1 answer:
motikmotik4 years ago
8 0

<u>Given</u>:

Given that the triangle ABC has vertices A(-2,3), B(0,3) and C(-1,-1).

We need to determine the coordinates of the image after a reflection over the x - axis.

Let A'B'C' denote the coordinates of the triangle after a reflection over the x - axis.

<u>Coordinates of the point A':</u>

The general rule to reflect the coordinate across the x - axis is given by

(x,y)\rightarrow (x,-y)

Substituting the point A(-2,3), we get;

(-2,3)\rightarrow (-2,-3)

Thus, the coordinates of the point A' is (-2,-3)

<u>Coordinates of the point B':</u>

The general rule to reflect the coordinate across the x - axis is given by

(x,y)\rightarrow (x,-y)

Substituting the point B(0,3), we get;

(0,3)\rightarrow (0,-3)

Thus, the coordinates of the point B' is (0,-3)

<u>Coordinates of the point C':</u>

The general rule to reflect the coordinate across the x - axis is given by

(x,y)\rightarrow (x,-y)

Substituting the point C(-1,-1), we get;

(-1,-1)\rightarrow (-1,1)

Thus, the coordinates of the point C' is (-1,1)

Hence, the coordinates of the image after a reflection over the x - axis is A'(-2,-3), B(0,-3) and C(-1,1)

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Step-by-step explanation:

<u>Linear Pair</u>

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<u>Alternate Interior Angle Theorem</u>

When two parallel lines are cut by a transversal, the alternate interior angles are congruent.

From inspection of the diagram, we can see that AB ║ DC.

Therefore, AE is the transversal.

So m∠A = 33°

<u>Sum of interior angles of a triangle is 180°</u>

Therefore, the top angle of the triangle = 180° - m∠A - 2x

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                                                                   = 147° - 2x

<u>Angles around a point add up to 360°</u>

⇒ 33° + m∠C + 5x + (147° - 2x) = 360°

⇒ 33° + 147° + 5x + 147° - 2x = 360°

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