68-33 blockers ?????????????????????????????????????????!?!!
This is easy to do because you can factor
example
6/2=3 because 6=2*3 so 6/2=3/1 times 2/2 or 3
2x^3+17x^2+23x-42 can be factored out to equal
(x-1)(x+6)(2x+7)
so [(x-1)(x+6)(2x+7)]/(2x+7)=[(x-1)(x+6)] times (2x+7)/(2x+7)=(x-1)(x+6)=x^2+5x-6
the answer is (x-1)(x+6) or x^2+5x-6
Answer:
What
Step-by-step explanation:
What language
Is that
Answer:
64
Step-by-step explanation:
f(x) = 4^x,
When x = 3,
=> f(3) = 4^3
= 4 * 4 * 4
= 64
Answer: -10 and 68
Step-by-step explanation:
We have the numbers, ordered from least to greatest:
11, 26, 29, 31, 43, 44, 47 and x.
The range is equal to the difference between the largest number and the smallest number, so, x can take two values.
The smallest number:
here we have that:
47 - x = 57
x = 47 - 57 = -10
The other possibility is that x is the largest number, in this case, we have that:
x - 11 = 57
x = 57 + 11 = 68.
Then the two possibla values of x are -10 and 68
