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2 years ago

What is the solution to the equation below? Vx + 3 = x - 3 A. 3 B. 6 C. 5 D. 4

Mathematics

1 answer:

kherson [118]2 years ago

6 0

Answer:

Step 1: Solve Square Root

Vx+3=x-3

x+3=(x-3)^2 (squared both sides)

x+3=x^2-6x+9

x+3-(x^2-6x+9)=0

(-x+1)(x-6)=0 (factor left side of equation)

-x+1=0 or x-6=0

x=1 or x=6

When you plug it in to check

1 (Doesn't Work)

6 (Work)

Therefore, 6 is your solution.

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Write a ratio, in the simplest form and a percent for the shaded area (there's a 5x4 box and 6 cubes are shaded)

Alexxandr [17]

Answer:

$\%Percent = 30 \%$

Step-by-step explanation:

Given

$Shaded = 6\ cubes$

$Box = 5\ x\ 4$

Required

Determine the percentage of the shaded cubes

First, we calculate the number of boxes:

$Box = 5\ x\ 4$

Express as multiplication

$Box = 5\ *\ 4$

$Box = 20$

This implies that there are 20 cubes in the box.

The percentage of the shaded cubes is:

$\%Percent = \frac{Shaded}{Box} * 100\%$

$\%Percent = \frac{6}{20} * 100\%$

$\%Percent = \frac{6* 100}{20} \%$

$\%Percent = \frac{600}{20} \%$

$\%Percent = 30 \%$

<em>30% were shaded</em>

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2 years ago

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zhuklara [117]

Answer:14

Step-by-step explanation:

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2 years ago

If a radius of a circle is perpendicular to a chord, then it _____ that chord.

labwork [276]

The answer is b. There is a proof, but it is easily got by proving the other cases wrong.

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Which of the following best describes the

ehidna [41]

$k:6x-14y=-28\ \ \ \ |subtract\ 6x\ from\ both\ sides\\\\-14y=-6x-28\ \ \ \ \ \ |divide\ both\ sides\ by\ (-14)\\\\y=\frac{-6}{-14}x-\frac{28}{-14}\\\\y=\frac{3}{7}x+2\\----------------------------\\l:3y-7x=-14\ \ \ \ \ |add\ 7x\ to\ both\ sides\\\\3y=7x-14\ \ \ \ \ \ |divide\ both\ sides\ by\ 3\\\\y=\frac{7}{3}x-\frac{14}{3}$

$Two\ lines\ are\ perpendicular\ if\ product\ of\ the\ slopes\ is\ equal\ -1.\\\\k:y=\frac{3}{7}x+2\to the\ skolpe\ m_k=\frac{3}{7}\\\\l:y=\frac{7}{3}x-\frac{14}{3}\to the\ slope\ m_l=\frac{7}{3}\\\\m_k\times m_l=\frac{3}{7}\times\frac{7}{3}=1\neq-1\\\\conclusion:the\ lines\ are\ not\ perpendicular\\\\Two\ lines\ are\ parallel\ if\ the\ slopes\ are\ equal.\\\\m_k=\frac{3}{7};\ m_l=\frac{7}{3}\to m_k\neq m_l\\\\conclusion:the\ lines\ are\ not\ parallel$

$Answer:\boxed{C-The\ lines\ intersect\ but\ are\ not\ perpendicular.}$

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Step2247 [10]

72% = 72/100

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