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trasher [3.6K]
3 years ago
13

What is the solution to the equation below? Vx + 3 = x - 3 A. 3 B. 6 C. 5 D. 4

Mathematics
1 answer:
kherson [118]3 years ago
6 0

Answer:

6

Step 1: Solve Square Root

Vx+3=x-3

x+3=(x-3)^2 (squared both sides)

x+3=x^2-6x+9

x+3-(x^2-6x+9)=0

(-x+1)(x-6)=0 (factor left side of equation)

-x+1=0 or x-6=0

x=1 or x=6

When you plug it in to check

1 (Doesn't Work)

6 (Work)

Therefore, 6 is your solution.

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Can somebody help answer this right plz!!!! (Grade7math)<br> (WILL MARK BRAINLIEST) <br> Thanks :)
notka56 [123]

Answer:

396°

Step-by-step explanation:

Difference = 357 -(-39) = 357+38 = 396°

8 0
3 years ago
Read 2 more answers
The amount of money spent on textbooks per year for students is approximately normal.
Ostrovityanka [42]

Answer:a

a

   336.04    <  \mu < 443.96

b

  The  margin of error will increase

c

The  margin of error will decreases

d

The 99% confidence interval is  0.4107 <  p  < 0.4293

Step-by-step explanation:

From the question we are  told that

   The sample size  n =  19

    The sample mean is  \= x  = \$\  390

    The  standard deviation is  \sigma =  \$ \  120

 

Given that the confidence level is  95% then the level of significance is mathematically represented as

           \alpha = 100 -  95

          \alpha  =  5 \%

          \alpha  =  0.05

Next we obtain the critical value of \frac{\alpha }{2} from the normal distribution table

    So  

         Z_{\frac{\alpha }{2} } =  1.96

The  margin of error is mathematically represented as

      E =  Z_{\frac{\alpha }{2} } *  \frac{\sigma}{\sqrt{n} }

=>    E = 1.96 *  \frac{120}{\sqrt{19} }

=>   E = 53.96

The 95% confidence interval is  

     \= x  -  E  <  \mu < \= x  +  E

=>   390  -   53.96   <  \mu < 390  -   53.96

=>  336.04    <  \mu < 443.96

When the confidence level increases the Z_{\frac{\alpha }{2} } also increases which increases the margin of error hence the confidence level becomes wider

Generally the sample size mathematically varies with margin of error as follows

         n  \  \ \alpha  \ \  \frac{1}{E^2 }

So if the sample size increases the margin of error decrease

The  sample proportion is mathematically represented as

       \r p  =  \frac{210}{500}

       \r p  = 0.42

Given that the confidence level is 0.99 the level of significance is  \alpha =  0.01

The critical value of \frac{\alpha }{2} from the normal distribution table is  

      Z_{\frac{\alpha }{2} }  =  2.58

  Generally the margin of error is mathematically represented as

       E =  Z_{\frac{\alpha }{2} }*  \sqrt{ \frac{\r p (1- \r p )}{n} }

=>   E =  0.42 *  \sqrt{ \frac{0.42 (1- 0.42 )}{ 500} }

=>     E =  0.0093

The 99% confidence interval  is

     \r p  -  E <  p  < \r p  +  E

     0.42  -  0.0093 <  p  < 0.42  +  0.0093

     0.4107 <  p  < 0.4293

 

4 0
4 years ago
2m·4b−3a·2n−0.2b·5m+n·5a−5bm+8an
cupoosta [38]

Answer:

2bm + 7an

Step-by-step explanation:

Multiply.

8bm - 6an - bm + 5an - 5bm + 8an

Combined like terms:

8bm - <em>6an</em> - bm + <em>5an</em> - 5bm + <em>8an</em>

= 2bm + 7an

8 0
3 years ago
10–{22–[(−9)+(−11)]} help i'M HAVING A bad day :( fix it
fredd [130]

Answer:

-32

Step-by-step explanation:

10–{22–[(−9)+(−11)]}

Work inside out

10–{22–[(-20)]}

Subtracting a negative is adding

10–{22+20}

10 - 42

-32

7 0
3 years ago
376097+345842875/505?
jeka57 [31]

Answer:

1060934.37624

Step-by-step explanation:

Nice troll question

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3 years ago
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