Step One
Find the base area of the large hexagon as though the smaller one was not removed.
Area = 3*Sqrt(3) * a^2 /2 where a is the length of one side of the hexagon
a = 5
Area = 3*sqrt(3) * 25/2 = 75 sqrt(3) / 2 of the large hexagon without the smaller one removed.
Step Two
Find the area of the smaller hexagon. In this case a = 4
Area2 = 3*sqrt(3)*16/2 = 3*sqrt(3)*8 = 24 sqrt(3)
Step Three
Find the area of the thick hexagonal area left by the removal of the small hexagon.
Area of the remaining piece = area of large hexagon - area of the small hexagon
Area of the remaining piece = 75 *sqrt(3)/2 - 24*sqrt(3)
Step Four
Find the volume of the results of the area from step 3
Volume = Area * h
h = 18
Volume = (75 * sqrt(3)/2 - 24*sqrt(3))* 18
I'm going to leave you with the job of changing all of this to a decimal answer. I get about 420 cm^3
Answer:
Step-by-step explanation:
area of square + 1/2 area of 1 triangle * 4
Answer:
24
Step-by-step explanation:
If this is an answer 24 because when there were 50 tickets sold there were 12 so when there is 100 tickets sold you double 12 to get 24
Hope this makes since and please do not come after me if this is wrong.
well, keeping in mind that twin sides stemming from the same "vertex" make twin angles at the "base", Check the picture below.
Answer:
1280
Step-by-step explanation:
rewrite (-8) times (-8) as an equivalent addition problem which is 8 times 8 = 64
take 64 then times it by 20 which is 64 times 20 equals 1,280
Hope this helps:)
