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Alona [7]
3 years ago
14

Plz help ill give u brainlist

Mathematics
1 answer:
g100num [7]3 years ago
3 0
Step One
Find the base area  of the large hexagon as though the smaller one was not removed.

Area = 3*Sqrt(3) * a^2 /2 where a is the length of one side of the hexagon
a = 5
Area = 3*sqrt(3) * 25/2 = 75 sqrt(3) / 2 of the large hexagon without the smaller one removed.

Step Two
Find the area of the smaller hexagon. In this case a = 4
Area2 = 3*sqrt(3)*16/2 = 3*sqrt(3)*8 = 24 sqrt(3)

Step Three
Find the area of the thick hexagonal area left by the removal of the small hexagon.

Area of the remaining piece = area of large hexagon - area of the small hexagon

Area of the remaining piece = 75 *sqrt(3)/2 - 24*sqrt(3)

Step Four
Find the volume of the results of the area from step 3
Volume = Area * h
h = 18
Volume = (75 * sqrt(3)/2 - 24*sqrt(3))* 18

I'm going to leave you with the job of changing all of this to a decimal answer. I get about 420 cm^3

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Answer:

a=4, b = -2

Step-by-step explanation:

Use elimination: subtract two equations. you get -6b = 12, so b = -2. Substitute this into the first equation and get a -8 = -4, so a = 4

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4 years ago
Solve for x given that <br><img src="https://tex.z-dn.net/?f=%20%7B64%7D%5E%7B2x%20-%201%7D%20%3D%20%20%7B32%7D%5E%7Bx%20%2B%201
marissa [1.9K]

Answer:

x = \frac{11}{7}

Step-by-step explanation:

note that 64 = 2^{6} and 32 = 2^{5} , thus

(2^{6}) ^{2x-1} = (2^{5}) ^{x+1} , that is

2^{6(2x-1)} = 2^{5(x+1)}

2^{12x-6} = 2^{5x+5}

Since the bases on both sides are equal, then equate the exponents

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7x - 6 = 5 ( add 6 to both sides )

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8 0
4 years ago
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Doss [256]
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In a G.P., the third term exceeds the first term by 16.
Tresset [83]

Answer:

Step-by-step explanation:

In a G.P, the nth term is given as

Un=ar^(n-1)

Where

a is first term

n is nth term

And r is common ratio

So in the question given above,

The third term exceed the first term by 16

i.e U3=U1+16

Where U1=a. First term

U3=a+16

Given also that, the sum if the third term and fourth term is 72.

Then U3+U4=72.

We are told to find common ratio (r)

U3=ar^3-1

U3=ar^2

Also, U4=ar^3

U3+U4=72

ar^2+ar^3=72

ar^2(1+r)=72. equation 1

Also for

U3=a+16

ar^2=a+16

ar^2-a=16

a(r^2-1)=16. From (x^2-y^2)=(x+y)(x-y)

Then,

a(r-1)(r+1)=16. Equation 2

Divide equation 2 by equation 1

a(r-1)(r+1)/ar^2(1+r) =16/72

Then a cancel a and (1+r) cancel (1+r)

So,

(r-1)/r^2=2/9

Cross multiply

9(r-1)=2r^2

2r^2-9r+9=0

Solving the quadratic equation

2r^2-6r-3r+9=0

2r(r-3)-3(r-3)=0

(r-3)(2r-3)=0

r-3=0. Or. 2r-3= 0

Then r=3 or r=3/2

8 0
3 years ago
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ASHA 777 [7]

Answer:

4^9

Step-by-step explanation:

6 0
3 years ago
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