Answer:
8626
Step-by-step explanation:
use a calculator in instead of here this was a EZ question but thanks for the points and if you have a harder question i'll be waiting
Answer:
2 x^4
Step-by-step explanation:
Recall that the GCF is the greatest of the product of factors that are common to all these three expressions
then for the pure numerical part, the factor common to 50, -10 , and 2 is "2"
and for the variable part x^4 is the largest common to all three expressions.
Therefore the GCF is: 2 x^4
Answer:
y = 3/5x + 62/5
Step-by-step explanation:
Equation of a line with two points is
m = y - y_1 / x - x _1
m = y_2 - y_1 / x_2 - x _1
Equating both
y - y_1 / x - x_1 = y_2 - y_1 / x_2 - x_1
Using what we are provided with
(-4 , 10)(16 , -2)
x_1 = -4
y_1 = 40
x_2 = 16
y_2 = -2
Imputing the values
10 - (-2) / 16 - (-4) = y - 10 / x - (-4)
10 + 2 /16 + 4 = y - 10 / x + 4
12 / 20 = y - 10 / x + 4
Lets cross multiply
12 ( x + 4) = 20(y - 10)
Open the brackets
12x + 48 = 20y - 200
12x + 48 + 200 = 20y
12x + 248 = 20y
Following this equation of line
y = mx + C
20y = 12x + 248
Let's divide through by 20 to get y.
20y / 20 = 12x + 248 / 20
y = 12x + 248 / 20
We can separate it by
y = 12x / 20 + 248 / 20
y = 3/5x + 62/5
Therefore, the equation of the line is
y = 3/5x + 62/5
We are given
v = 18 m/hr west
θ1 = 285°
θ2 = 340°
After 1 hours, the distance traveled by the ship is
dv = 18 mi
The distance between the ship and the lighthouse is
d = 18 / cos 340
Solve for d<span />
I think it’s 8 ( I’m not sure )
