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sukhopar [10]
3 years ago
14

A box contains only black and white chips. There are 8 black chips and 6 white chips. How many white chips must be removed so th

at the possibility of randomly picking a black chip becomes 2/3 ?
A) 1
B) 2
C) 3
D) 4
HELP ME PlZzzzzzz whoever answers this right gets the brainliest
Mathematics
1 answer:
3241004551 [841]3 years ago
5 0

There are 8 black chips and 6 white chips, 14 chips in total. In this situation the probability to pick a black chip is 8/14=4/7.

When one white chip was removed, then only 5 white chips left and the total number of chips became 13. In this situation the probability to pick a black chip is 8/14=4/7.

When second white chip was removed, then ther left 4 white chips and the total number of chips became 12. Now the probability to pick a black chip is 8/12=2/3 as needed.

Answer: Must be removed 2 white chips. Correct choice is B.


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Answer & Step-by-step explanation:

The domain is the input, and the range is the output.

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<em>domain: {4, -1, 0, 2}</em>

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7 0
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Match the expressions with the nonpermissible replacements for y
pantera1 [17]

<em>-7 _D_</em>

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<em>_A_ \frac{y^{2} -2y+1}{2y-3}</em>

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<em>_D_ \frac{y^{2}-y-6 }{-2(y+7)}</em>


3 0
3 years ago
Read 2 more answers
What is the answer to this
Vika [28.1K]

Answer:

The upper one is 8, the lower one is 6

7 0
3 years ago
Is 7/12 bigger than 1/2
Varvara68 [4.7K]
Lets think of it this way:-

1/2 is one half

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Now, 7 is greater than 6, which means the fraction 7/12 is greater than 1/2

Answer: 7/12 is bigger 
7 0
3 years ago
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