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sukhopar [10]
3 years ago
14

A box contains only black and white chips. There are 8 black chips and 6 white chips. How many white chips must be removed so th

at the possibility of randomly picking a black chip becomes 2/3 ?
A) 1
B) 2
C) 3
D) 4
HELP ME PlZzzzzzz whoever answers this right gets the brainliest
Mathematics
1 answer:
3241004551 [841]3 years ago
5 0

There are 8 black chips and 6 white chips, 14 chips in total. In this situation the probability to pick a black chip is 8/14=4/7.

When one white chip was removed, then only 5 white chips left and the total number of chips became 13. In this situation the probability to pick a black chip is 8/14=4/7.

When second white chip was removed, then ther left 4 white chips and the total number of chips became 12. Now the probability to pick a black chip is 8/12=2/3 as needed.

Answer: Must be removed 2 white chips. Correct choice is B.


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Answer:

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Step-by-step explanation:

Since the plane traveled due west,

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Represent that with θ

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θ = 139.17.

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Since, θ is opposite side C, side C can be calculated using cosine formula as;

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Substitute values for A, B and θ

C² = 150² + 170² - 2 * 150 * 170 * Cos 139.17

C² = 22500 + 28900 - 51000 * Cos 139.17

C² = 51400 - 51000 (−0.7567)

C² = 51400 + 38,591.7

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C = 299.99 miles (Approximated)

Hence, the distance between the plane and the airport is 299.99 miles

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Check the picture below.

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