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3 years ago

9

Inga read 20 books last summer, and Gordon read 5 books. Which statement comparing the number of books Inga and Gordon read is a

ccurate?

1 answer:

Lina20 [59]3 years ago

3 0

The accurate statement is the first one, which is "Igna read 4 times as many books as Gordon."

Mark brainliest if I helped you

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Thanks for help have nice day

kupik [55]

Answer: 6. d

7. b

8. d

9. c

Step-by-step explanation:

8 0

2 years ago

The lengths of two sides of a triangle are 15 inches each. The third side measures 10 inches. What type of triangle is this? Exp

zloy xaker [14]

Answer: Isosceles

<u>Step-by-step explanation:</u>

When two sides of a triangle are congruent, it is an isosceles triangle.

When three sides of a triangle are congruent, it is an equilateral triangle.

5 0

2 years ago

Four friends together bought 126 acres of

Softa [21]

Answer:

31.5 acres

Step-by-step explanation:

7 0

2 years ago

Explain why x^2 + y^2 -6x +10y = -34 is NOT a circle. What is it?

kenny6666 [7]

Answer:

(See explanation for further details)

Step-by-step explanation:

The expression is transformed into its standard form:

$x^{2} + y^{2} - 6\cdot x + 10\cdot y + 34 = 0$

$x^{2} - 6\cdot x + 9 + y^{2} + 10\cdot y + 25 = 0$

$(x-3)^{2} + (y+5)^{2} = 0$

The function does not represent a circle, as radius is a positive number.

4 0

3 years ago

Look at this cylinder:

Sedbober [7]

Height=h=8cm
Radius=r=4cm

We know

$\boxed{\sf \star TSA_{(Cylinder)}=2\pi r(h+r)}$

$\\ \sf\longmapsto TSA_{(Old\:Cylinder)}=2\times \dfrac{22}{7}\times 4(8+4)$

$\\ \sf\longmapsto TSA_{(Old\:Cylinder)}=\dfrac{176}{7}(12)$

$\\ \sf\longmapsto TSA_{(Old\:Cylinder)}=\dfrac{2112}{7}$

$\\ \sf\longmapsto TSA_{(Old\:Cylinder)}=301.7cm^2$

Now

New Radius=2(4)=8cm
New Height=2(8)=16cm

$\\ \sf\longmapsto TSA_{(New\:Cylinder)}=2\times \dfrac{22}{7}\times 8(16+8)$

$\\ \sf\longmapsto TSA_{(New\:Cylinder)}=\dfrac{352}{7}(24)$

$\\ \sf\longmapsto TSA_{(New\:Cylinder)}=\dfrac{8448}{7}$

$\\ \sf\longmapsto TSA_{(New\:Cylinder)}=1204.7cm^2$

So

$\\ \sf\longmapsto \dfrac{TSA_{(New\:Cylinder)}}{TSA_{(Old\:Cylinder)}}=\dfrac{1204.7}{301.7}$

$\\ \sf\longmapsto \dfrac{TSA_{(New\:Cylinder)}}{TSA_{(Old\:Cylinder)}}=\dfrac{4}{1}$

$\\ \sf\longmapsto\underline{\boxed{\bf{ {TSA_{(New\:Cylinder)}}:{TSA_{(Old\:Cylinder)}}=4:1}}}$

Hence our correct option is Option C

6 0

2 years ago