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alexgriva [62]
3 years ago
8

Find the value of x. 25 points

Mathematics
2 answers:
Novay_Z [31]3 years ago
8 0
Answer: X=110°
Explanation: The circumference of a quadrilateral is 360°
128+40+82=250
360-250=110
densk [106]3 years ago
5 0
The sum of the angles in a quadrilateral is 360 degrees.

So take 360 - 40 - 128 - 82 = 110 degrees

x = 110
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A square has a side length of 36 feet.This square is dilated by a scale factor of 2/3 to create a new square .What is the side l
Vaselesa [24]

Answer:

24 ft

Step-by-step explanation:

36 x 2/3= 24

It is dilated by a scale of 2/3 which means it will be smaller.

8 0
4 years ago
Robert makes $951 gross income per week and keeps $762 of it after tax withholding. How many allowances has Robert claimed? For
MAXImum [283]

Answer:

Option D,four is correct

Step-by-step explanation:

The tax withholding from the gross income of $951 is the gross income itself minus the income after tax withholding i.e $189  ($951-$762)

The percentage of the withholding =189/951=20% approximately

Going by the multiple  choices provided,option with 4,189 dollars seems to the correct option as that is the exact of the tax withholding on Robert's gross income and his earnings fall in between $950 and $960

4 0
3 years ago
How many times longer is the wavelength of a sound wave with a frequency of 20 waves per second than the wavelength of a sound w
sergejj [24]

The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec

<h3>Calculating wavelength </h3>

From the question, we are to determine how many times longer is the first sound wave compared to the second sound water

Using the formula,

v = fλ

∴ λ = v/f

Where v is the velocity

f is the frequency

and λ is the wavelength

For the first wave

f = 20 waves/sec

Then,

λ₁ = v/20

For the second wave

f = 16,000 waves/sec

λ₂ = v/16000

Then,

The factor by which the first sound wave is longer than the second sound wave is

λ₁/ λ₂ = (v/20) ÷( v/16000)

= (v/20) × 16000/v)

= 16000/20

= 800

Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec

Learn more on Calculating wavelength here: brainly.com/question/16396485

#SPJ1

6 0
2 years ago
Name the postulate or theorem you can use to prove
gladu [14]

AAS

A for <SUR and <TVR

A for <SRU and <TRV

S for SU and TV

6 0
3 years ago
Read 2 more answers
Pls help I'll give brainliest!
natali 33 [55]

Answer:

95

Step-by-step explanation:

t_n =  {n}^{2}  - 5 \\  \therefore \: t_{10} =  {10}^{2}  - 5 \\ \therefore \: t_{10} = 100  - 5 \\ \huge \red{ \boxed{\therefore \: t_{10} = 95 }}\\

10th term of the sequence is 95.

3 0
3 years ago
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