5x-3x^2/2x^4 =x(5-3x) / 2x.(x^3), simplified by x, we have <span>5-3x/2x^3, (x≠0)
</span>so the answer is <span>C.5-3x/2x^3, (x≠0)</span>
Answer:
<u>5/4</u>
Step-by-step explanation:
Given :
- tanθ = 3/4 = opposite/adjacent
Finding the missing side :
- The hypotenuse must be found
- √3² + 4²
- √25
- 5
Taking the sec ratio :
- secθ = hypotenuse/opposite
- secθ = <u>5/4</u>
Answer:
a
Step-by-step explanation:
(ax-by)²+(bx+ay)²
a²x²-2axby+b²y²+b²x²+2axby+a²x²
a²x²+b²x²+b²y²+a²x²
(a²+b²)x²+(a²+b²)y²
(a²+b²)(x²+y²)
Answer:
y=log_2 (x)
Step-by-step explanation:
We see that the graph passes though the point (2,1). So we can write:
log_a (2) = 1 => a = 2
So it's a log in base 2.
