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3 years ago

Anyone out there can solve this I will give 17 points!!!

Mathematics

2 answers:

irinina [24]3 years ago

7 0

Answer:

D K + 2K = 51

Step-by-step explanation:

Lauren is twice Kristy's age so it would be 2K cause you want to multi[ly, and then you have to add Kristy's age in the equation because their ages added together is 51

vichka [17]3 years ago

6 0

Answer:

D. K+2K=51

Step-by-step explanation:

Since Lauren is 2 times Kristy's age, Lauren's age=2K

so, if the sum of the two is 51, then 2K+K=51

If you want to solve it, 2K+K=3K=51

51/3=K

17=K

34=L

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3+x=2–3x how many solutions and the answer thank you

trasher [3.6K]

Answer:

there are only 1 and that is x=-1/4

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Please help i will mark as brainliest

gulaghasi [49]

Answer:

162 mL

Step-by-step explanation:

1.Convert all volumes to millilitres

(a) Chlorpheniramine

V = 100 mL

(b) Lidocaine

V = \text{2 oz} \times \dfrac{\text{29.57 mL}}{\text{1 oz}} = \text{ 59.14 mL)

(c) Banana flavouring

V = \dfrac{1}{2}\text{ tsp} \times \dfrac{\text{4.93 mL}}{\text{1 tsp}} = \textbf{2.46 mL} }

2.Calculate the total volume

Chlorpheniramine = 100 mL

Lidocaine = 59.14

Banana flavouring = <u> 2.46 </u>

TOTAL = 162 mL

7 0

4 years ago

Suppose the weights of the Boxers at this club are Normally distributed with a mean of 166 pounds and a standard deviation of 5.

lesya [120]

Answer:

0.1994 is the required probability.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 166 pounds

Standard Deviation, σ = 5.3 pounds

Sample size, n = 20

We are given that the distribution of weights is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

Standard error due to sampling =

$=\dfrac{\sigma}{\sqrt{n}} = \dfrac{5.3}{\sqrt{20}} = 1.1851$

P(sample of 20 boxers is more than 167 pounds)

$P( x > 167) = P( z > \displaystyle\frac{167 - 166}{1.1851}) = P(z > 0.8438)$

$= 1 - P(z \leq 0.8438)$

Calculation the value from standard normal z table, we have,

$P(x > 167) = 1 - 0.8006= 0.1994 = 19.94\%$

0.1994 is the probability that the mean weight of a random sample of 20 boxers is more than 167 pounds

3 0

3 years ago

PLZ ANSWER AS SOON AS YOU CAN ITS ONLY 3 QUESTIONS

densk [106]

1 is really b, I just learned this
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4 years ago

A taxi cab in myrtle beach charges 2$ per mile and 1$ for every person. If a taxi cab ride for two people costs $12 how far did

Dima020 [189]

Answer:

The total number of miles traveled was 5 miles.

Step-by-step explanation:

1 x 2 = 2 people

12 - 2 = 10

10 divided by 2 = 5 miles

So the total number of miles traveled was 5 miles.

8 0

3 years ago