Given:
The given digits are 1,2,3,4,5, and 6.
To find:
The number of 5-digit even numbers that can be formed by using the given digits (if repetition is allowed).
Solution:
To form an even number, we need multiples of 2 at ones place.
In the given digits 2,4,6 are even number. So, the possible ways for the ones place is 3.
We have six given digits and repetition is allowed. So, the number of possible ways for each of the remaining four places is 6.
Total number of ways to form a 5 digit even number is:
Therefore, total 3888 five-digit even numbers can be formed by using the given digits if repetition is allowed.
<span>Simplifying
w + -11 = 1.3
Reorder the terms:
-11 + w = 1.3
Solving
-11 + w = 1.3
Solving for variable 'w'.
Move all terms containing w to the left, all other terms to the right.
Add '11' to each side of the equation.
-11 + 11 + w = 1.3 + 11
Combine like terms: -11 + 11 = 0
0 + w = 1.3 + 11
w = 1.3 + 11
Combine like terms: 1.3 + 11 = 12.3
w = 12.3
Simplifying
w = 12.3 <--- (Answer)
Happy studying ^-^</span>
The distance are
a. 42.42
b. 15. 52
<h3>How to solve for the distance</h3>
80 = 65 + <ABC
<ABC = 80 - 65
= 15
Through the use of sine rule we would have
By using sine rule,
Sine 15/a = sine 135/b =
sin 30/30.
Next we have to solve b by cross multiplying
b = (30× sin135) / sin 30
= 21.21/0.5
b = 42.42 km
Also, the value of a will be:
= (42.42 × sin 15) / sin 135
= 10.98/0.7071
= 15.52
Read more on bearing here:
brainly.com/question/15221233
#SPJ1
Answer:
3.650282
Step-by-step explanation:
Google is a very powerful tool, use it
I think k equals negative 2, or -2.<span>
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